Answer:
It might be responding variable.
Answer:
The answer to your question is: letter c
Explanation:
Data
V1 = 612 ml n1 = 9.11 mol
V2 = 123 ml n2 = ?
Formula
![n2 = \frac{n1V2}{V1}](https://tex.z-dn.net/?f=n2%20%3D%20%5Cfrac%7Bn1V2%7D%7BV1%7D)
![n2 = \frac{(9.11)((123)}{(612)}](https://tex.z-dn.net/?f=n2%20%3D%20%5Cfrac%7B%289.11%29%28%28123%29%7D%7B%28612%29%7D)
n2 = 1.83 mol
Answer:
0.080 mol
Explanation:
M(HCl) = (1.0 +35.5) g/mol = 36.5 g/mol
2.9g*1mol/36.5 g = 0.0795 mol HCl
Ca(OH)2 + 2HCl ---> CaCl2 + 2H2O
from reaction 2 mol 2 mol
given 0.0795 mol x mol
x = 0.0795 mol ≈0.080 mol
Explanation:
when one reactants is in excess, there will always be some left over. The other reactants becomes limiting factor and controls show much of each product is produced.while using excess percentage yields this is at the expense of atom economy.
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