All categories

3 years ago

Talbot Family has a monthly income of $3,200. They spend $800 on rent what percentage of the Talbot family is spent of rent?

Mathematics

1 answer:

guapka [62]3 years ago

6 0

Answer:

800/3200= .25 or 25%

you must divide the rent by the monthly income.

You might be interested in

I'm confused... The cost in dollars of an n-mile trip with Supreme Taxi Service is given by 1.5+1.75n. 1.5 plus 1.75 n The cost

salantis [7]

the town taxi service would be cheapest because you choose a number 1-10 and plug it into N for both equations and see which taxi service is cheaper for miles 1-10 and than it will change for longer distance taxi rides and be the Supreme town taxi service!

The town taxi service is the answer

Hope this helped!!

6 0

3 years ago

Read 2 more answers

Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5

hjlf

The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5

5 0

3 years ago

34 feet converted to yards and feet

Julli [10]

Answer:

11 yards and 1 foot

Step-by-step explanation:

34 divided by 3

4 0

3 years ago

Read 2 more answers

Which term of a AP 5 , 13 , 21 ,... is 181?

Sauron [17]

Here,a(n) = a + (n-1)d
Here, a = 5, d = 12-5 = 8, a(n) = 181
Substitute this values in to the expression,

181 = 5 + (n-1)8
181-5 = 8n-8
176+8 = 8n
n = 184/8
n = 23

So, it is 23th term of that Arithmetic Progression.

Hope this helps!

7 0

3 years ago

One of the tallest living men has a height of 236 cm. One of the tallest living women is 224 cm tall. Heights of men have a mean

Roman55 [17]

Answer:

A. The woman is relatively taller because the z score for her height is greater than the z score for the man's height.

Step-by-step explanation:

Whoever has the highest z-score, is taller relative to the population of the same gender.

The z-score of a value X in a set with mean $\mu$ and standard deviation $/sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

Solution:

Heights of men have a mean of 170 cm and a standard deviation of 6 cm. One of the tallest living men has a height of 236 cm. So the z-score of his height is:

$Z = \frac{X - \mu}{\sigma} = \frac{236-170}{6} = 11$

Heights of women have a mean of 161 cm and a standard deviation of 5 cm.

One of the tallest living women is 224 cm tall. The z-score of the women's height is

$Z = \frac{X - \mu}{\sigma} = \frac{224-161}{5} = 12.6$

The women has a higher z-score, so she is relatively taller.

The correct answer is A

3 0

4 years ago