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3 years ago

I give 10 points and brainliest

Mathematics

2 answers:

Maksim231197 [3]3 years ago

7 0

(5,-9)
Thats the answer

cestrela7 [59]3 years ago

5 0

Answer:(5,-9)

Step-by-step explanation:

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I need help solving |5+2j|=9 please

V125BC [204]

$5 + 2j = 9 \\ j = 2$
$5 + 2j = - 9 \\ j = - 7$

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3 years ago

I need help fast if you help I will mark you as Brainlist

stira [4]

Answer:

The answer is C

Step-by-step explanation:

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3 years ago

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The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is re

balandron [24]

Answer:

0.013 = 1.3% probability that fifteen employees must be tested in order to find three positives.

Step-by-step explanation:

For each employee, there are only two possible outcomes. Either they test positive, or they do not. The probability of an employee testing positive is independent of any other employee, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

40% of the employees have positive indications of asbestos in their lungs

This means that $p = 0.4$

Find the probability that fifteen employees must be tested in order to find three positives.

2 during the first 14(given by P(X = 2) when n = 14).

The 15th is positive, with 0.4 probability. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{14,2}.(0.4)^{2}.(0.6)^{12} = 0.0317$

0.0317*0.4 = 0.013.

0.013 = 1.3% probability that fifteen employees must be tested in order to find three positives.

7 0

3 years ago

Alligators captured in Florida are found to have a mean length of 2 meters and a standard deviation of 0.35 meters. The lengths

STALIN [3.7K]

Answer:

The correct option is (d). 2.15 meters.

Step-by-step explanation:

According to the given scenario, the approximate length of an alligator at the 67th percentile is as follows:

The length of an alligator is $X \sim N(2,0.35)$ .

Let us assume the $P_{67}$ be the 67th percentile

$P(X$

$\frac{P_{67 - 2 }}{0.35} = 0.44\\\\P_{67} = 2.154$

Hence, the correct option is (d). 2.15 meters

5 0

3 years ago

Solve the equation:

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

$4\sqrt{3-\frac{1}{x} } -\sqrt{\frac{x}{3x-1} } =3\\4\sqrt{\frac{3x-1}{x} } -\sqrt{\frac{x}{3x-1} } =3\\\\put ~\sqrt{\frac{3x-1}{x}} =a\\4a-\frac{1}{a} =3\\4a^2-1-3a=0\\4a^2-4a+1a-1=0\\4a(a-1)+1(a-1)=0\\(a-1)(4a+1)=0\\a=1,-\frac{1}{4}\\$

$\sqrt{\frac{3x-1}{x} } =1\\3x-1=x\\3x-x=1\\2x=1\\x=\frac{1}{2}$

when a=-1/4

$\sqrt{\frac{3x-1}{x} } =-\frac{1}{4} \\$

$\frac{3x-1}{x} =\frac{1}{16} \\48x-16=x\\47x=16\\x=\frac{16}{47}$

$\frac{(1-2x)^2 \times (x^2-9)}{-x^2-x+6} \geq 0,\\both ~numerator ~and~denominator ~are~of~same~sign.\\\frac{(1-2x)^2(x^2-9)}{-x^2-3x+2x+6} \geq 0\\\frac{(1-2x)^2(x+3)(x-3)}{-x(x+3)+2(x+3)} \geq 0\\\frac{(1-2x)^2(x+3)(x-3)}{(x+3)(-x+2)} \geq 0\\(1-2x)^2\geq 0~(always)\\x\neq -3\\case.~1.\\both~numerator~and~denominator >0\\\frac{x-3}{-x+2} \geq 0\\x-3\geq 0\\x\geq 3\\-x+2> 0\\-x>-2\\x$

case 2.

both numerator and denominator are negative.

$x-3\leq 0\\x\leq 3\\-x+2\leq 0\\-x\leq -2\\x\geq 2\\solution~is~(-\infty,-3)U(-3,3]U[2,\infty)$

5 0

3 years ago

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