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3 years ago

Please help I’m stuck on this question

Mathematics

1 answer:

yan [13]3 years ago

3 0

It helps demonstrate it since it forms a right triangle in the middle with 2 base lengths and a hypotenuse. The areas of the squares can be plugged into the pythagorean theorem in order to find the answer

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I need help on this question, someone please help!!

Tju [1.3M]

Answer:

y=−x−1/3x−8

Step-by-step explanation:

y=8x−1/3x+1

To find the inverse function, swap x and y, and solve the resulting equation for x.

If the initial function is not one-to-one, then there will be more than one inverse.

So, swap the variables: y=8x−1/3x+1 becomes x=8y−1/3y+1.

Now, solve the equation x=8y−1/3y+1 for y.

y=−x−1/3x−8

Sorry I was in a rush and couldn't do the fractions as formulae. Hope it helped anyways.

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3 years ago

-6 د3 ( 3 د4 – 2 د3 – د + 9 )

iren [92.7K]

Answer:

...............

Step-by-step explanation:

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3 years ago

A pack of six cans of coffee cost 12$ . How much would 15 cans of coffee cost

Vera_Pavlovna [14]

$30 because 12/6 = 2 so 15 x 2 = 30

4 0

3 years ago

A photograph measuring 4 inches wide and 5 inches long is enlarged to make a wall mural. If the mural is 82 inches wide, how lon

Aliun [14]

I say it around 150 inches that what I think

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3 years ago

Evaluate the triple integral. 5x dv, where e is bounded by the paraboloid x = 7y2 + 7z2 and the plane x = 7. e

Mrac [35]

Convert to cylindrical coordinates:

$x=x$

$y=r\cos\theta$

$z=r\sin\theta$

Then $E$ is the set of points $(r,\theta,x)$ such that $0\le r\le1$ , $0\le\theta\le2\pi$ , and $7y^2+7z^2\le x\le7$ or $7r^2\le x\le7$ .

Now

$\displaystyle\iiint_E5x\,\mathrm dV=5\int_0^{2\pi}\int_0^1\int_{7r^2}^7xr\,\mathrm dx\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{245\pi}3}$

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3 years ago