The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Answer:
A score of 117 is needed, which Is not possible since the test is over 100.
Step-by-step explanation:
The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.
Therefore ( 85 + 94 + 84 + X)/4 =95
Then 263+X /4 =95
Cross mutiplying 4*95=263+X
Therefore X= 380-263
X= 117 which is not possible since the test score is over 100.
Answer:
x = 4 y = 2✓3
Step-by-step explanation:
I'm big brain
Answer:
x=1/2
Step-by-step explanation:
10-2x=14x+2
8/16=16x/16
x=1/2
