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Marysya12 [62]
3 years ago
8

Write a balanced chemical equation for the incomplete combustion of gaseous ethane (C2H6). What is the sum of the coefficients i

n this balanced chemical equation
Chemistry
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:

C2H6 +02 ===>Co2 + H20.

Explanation:

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Convert 4.00 atm to mmHg
Ksivusya [100]

Answer:

3040 mmHg

Explanation:

Here

we have to convert 4.00 atm to mmHg

As we know that

The number of atm in 1 mmHg is 0.0013157895567935

Now there is 4.00 atm So, in mmHg it would be

And, according to this, the working is given below:

= 4 ÷ 0.0013157895567935

= 3,039.99

= 3040 mmHg

Hence, the last option is correct

And, the same is relevant and considered too

3 0
2 years ago
The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The c
dem82 [27]

Answer:

The work is  

      W = -0.369kJ

The energy  change of the reaction is  \Delta U _{rxn} = 43.839 kJ  

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             2 Cu_2 O + O_2_{(g)} ----> 4 CuO_{(s)}

     The mass of  Cu_2 O is  m = 42.60g

      The enthalpy Cu_2 O is  \Delta H_{re} = -43.47 \ kJ this also the change in energy in terms of heat

      The pressure at which it is oxidized is P = 1\  bar

The  no of moles of Cu_2 Oused in this reaction is mathematically represented as

        n = \frac{mass \ of   \ Cu_2 O}{Molar \ mass \  of   \ Cu_2 O}

The molar mass of Cu_2 O is  a constant with a value  M = 143.1 g/mol

   Now substituting values

             n = \frac{ 42.60}{143.1}

            n = 0.29769 \ moles

From the reaction we see that

Two mole of Cu_2 O  reacts with One mole of O_2 to give Four moles of  CuO_{(s)}

This means that

One mole of  Cu_2 O  reacts with 0.5 mole of O_2 to give two moles of  CuO_{(s)}

it also implies that

0.29769 \ mole of  Cu_2 O  reacts with 0.5 * 0.29769 moles of O_2 to give 2* 0.29769 moles of  CuO_{(s)}

so

0.29769 \ mole of  Cu_2 O  reacts with 0.149 moles of O_2 to give 0.595 moles of  CuO_{(s)}

Now the number of moles of gaseous reactant is

      N_{O_2} = 0.149 \ moles

The number of moles of gaseous product  is

     N_p = 0 \ moles

So the change in number of moles for gaseous  compounds is mathematically evaluated as

         \Delta N = 0- 0.149 \ moles

        \Delta N = - 0.149 \ moles

Now the workdone for  the compound Cu_2 O is mathematically represented as

        W = \Delta N RT

Where R is the gas constant with a value of R = 8.314 J/mol \cdot K

            T is the temperature with a value  T = 25 + 273 = 298 K

     Substituting values

     W = -0.149 * 8.314 * (298)

     W = -0.369kJ

Generally the internal energy change of the reaction can be represented as

           \Delta U _{rxn} = \Delta H_{re} - W

Substituting value

        \Delta U _{rxn} = -43.47 -  (-0.369)

        \Delta U _{rxn} = 43.839 kJ  

This is the internal energy change on the reaction for 42.60 g of Cu_2 O

       

3 0
3 years ago
Q1.
kicyunya [14]

Answer:

CuCO3 (s)

H2O (l)

................

5 0
3 years ago
What does it mean for a weak acid to be in equilibrium
ipn [44]
When an uncharged weak acid is added to water, a homogeneous equilibrium forms in which aqueous acid molecules, HA(aq), react with liquid water to form aqueous hydronium ions and aqueous anions, A-<span>(aq). The latter are produced when the acid molecules lose H+ ions to water.</span>
7 0
3 years ago
Read 2 more answers
Chemical bonds are formed when potential energy is when it’s High or Low?
Natalka [10]

Answer:

high I think

Explanation:

i just did it

3 0
2 years ago
Read 2 more answers
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