We need to keep in mind that the compound is neutral.
H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4
Therefore the oxidation number for sulfur is +4.
Answer:
The net ionic equation for the given reaction :

Explanation:
...[1]
..[2]
...[3]

Replacing
, NaI and
in [1] by usig [2] [3] and [4]

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

Answer:
The substances to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The presence of the arrow also indicates that the reaction goes in one direction under the conditions indicated.
Explanation:
Answer: it is part of newtons second law. so the object to your question would accelerate
Explanation: newtons second law
Explanation:
Moving from left to right across a period, the atomic radius decreases. The nucleus of the atom gains protons moving from left to right, increasing the positive charge of the nucleus and increasing the attractive force of the nucleus upon the electrons.