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Rama09 [41]
3 years ago
14

Which of the measurement contain three significant figure?

Chemistry
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

The answer is explained below

Explanation:

The question is not complete.

The correct question should be like:

Which of the measurement contain three significant figure?

500

395

0.001

0.00100

1 × 10⁻³

5 × 10²

Answer:

The following are rules applied when considering significant figures:

i) All digits are significant excluding zero. E.g of significant digits are 1,2,3,4,5,6,7,8,9

ii) Any zero that appear within or after non zero digits are significant e.g. 200, 1004, 500009

iii) Zeros before non zero digits are not significant. An example shows significant digits bolded 001,  0.0012, 001.56

iv) Zeros that come after non zero digits are significant even if the number is in decimal form. An example shows significant digits bolded 1000,  0.001200, 001.5600

Therefore:

500: It contains three significant digits

395: It contains three significant digits

0.001:  It contains only one significant digits

0.00100: It contains three significant digits

1 × 10⁻³: 1 × 10⁻³ = 0.001.  It contains only one significant digits

5 × 10²: 5 × 10² = 500. It contains three significant digits

The measurements that contain three significant figure are 500, 395, 0.00100 and 5 × 10²

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If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

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Does Monocercomonoides still meet the definition of a eukaryote? Why or why not?
KengaRu [80]

Answer:

Yes

Explanation:

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They are significant because they challenge the idea that eukaryotes need mitochondria to be classified as eukaryotic. However, they have other membrane-bound organelles such as a nucleus and Golgi apparatus, meaning they remain eukaryotic.

Research suggest they lost their mitochondria over time, rather than never having had them throughout their ancestry.

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How does increasing pressure affect the rate of reaction between gases?
Elina [12.6K]

Answer:

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Explanation:

7 0
2 years ago
What is the volume of 8.7 * 10 ^ 23 molecules of chlorine gas (Cl 2 ) ?
Mariana [72]

Answer:

32.3 dm³

Explanation:

Data given:

no. of molecules of Cl₂ = 8.7 x 10²³

Volume of chlorine gas (Cl₂) = ?

Solution:

First we have to find number of moles

For this formula used

    no. of moles = no. of molecules / Avogadros number

    no. of moles = 8.7 x 10²³ / 6.022 x 10²³

    no. of moles = 1.44 moles

Now we have to find volume of the gas

for this formula used

                      no. of moles = volume of gas / molar volume

molar volume = 22.4 dm³/mol

Put values in above equation

                 1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol

rearrange the above equation

                 volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol

                volume of Cl₂ gas =  32.3 dm³

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