Question

a race car is driving under the caution flag at 440 feet per second begins to accelerate at a constant rate after the warning flag. the distance traveled since the warning flag in feet is characterized by 30t^2+440t, where t is the time in seconds after the car starts accelerating again. How long will the car take to travel 150 feet?

Answer 1

Answer: $\frac{1}{3}\ s$

Step-by-step explanation:

Given

Distance traveled is $s=30t^2+440t$

for s=150 ft

$\Rightarrow 30t^2+440t=150$

$\Rightarrow 30t^2+440t-150=0\\\Rightarrow 3t^2+44t-15=0\\\Rightarrow (3t-1)(t+15)=0\\\Rightarrow t=\dfrac{1}{3}\ s$