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2 years ago

The black graph is the graph of y=f(x). Choose the equation for the red graph

Mathematics

1 answer:

Ghella [55]2 years ago

5 0

Answer:

a. y= f(x-1)

Step-by-step explanation:

___________

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What is the sum of 1/3 + 5 3/4 as a mixed number in simplest form

mart [117]

6 1/12 would be the answer

Rewriting our equation with parts separated

1/3+5+3/4

Solving the fraction parts

1/3+3/4=?

Find the LCD of 1/3 and 3/4 and rewrite to solve with the equivalent fractions.

LCD = 12

4/12+9/12=13/12

Simplifying the fraction part, 13/12,

13/12=11/12

Combining the whole and fraction parts

5+1+1/12=6 1/12

3 0

3 years ago

ASAP!<br> find the slope of a line that is perpendicular to y=-1/2x+4

aliya0001 [1]

We know that :

Ф Product of the slopes of two lines perpendicular to each other should be equal to -1

Let the slope of the line perpendicular to given line be : M

Given equation of the line : y = -1/2x + 4

This line is in the form : y = mx + c, where m is the slope and c is the y intercept

Comparing with y = mx + c :

we can notice that slope of the given line is -1/2

⇒ M × -1/2 = -1

⇒ M × 1/2 = 1

⇒ M = 2

<u>Answer</u> : Slope of the line perpendicular to given line is 2

8 0

3 years ago

Simplify: i) (a + b)(5a – 3b) + (a – 3b)(a – b) ii) (a – b) (a2 + b2 + ab) – (a + b) (a2 + b2 – ab) iii) (b2 – 49) (b + 7) + 343

marin [14]

Answer:

plz mark brainliest✌️✌️

8 0

2 years ago

Find the percent of decrease from 87 pounds to 16 pounds. Round to the nearest tenth of a percent if necessary. Should be in per

irina1246 [14]

Answer:

81.6

Step-by-step explanation:

7 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

$x^3y'' + 2x^2y' + 4y$

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ; $x=x_o$ is located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

$y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0$

$y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0$

The standard form of the differential equation is :

$\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0$

Thus;

$P(x) = \dfrac{2}{x}$

$Q(x) = \dfrac{4}{x^3}$

The zeros of $x,x^3$ is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x) and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = $x*\dfrac{2}{x}$

p(x) = 2

q(x) = x²Q(x)

q(x) = $x^2 * \dfrac{4}{x^3}$

q(x) = $\dfrac{4}{x}$

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic at x = 0

$Q(x) = \dfrac{4}{x^3}$ do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0

3 years ago