The length and mass of the arm are Larm = X1 = 50 cm and Marm = 0.3 kg, X2 = 15 cm, and the mass of the object is MObject = 0.25
kg. For this problem you may assume that the hook at the end of the arm is massless and the gravitational constant can be approximated as g = 10 m/s2 Develop a symbolic expression for the torque required by the motor to lift the object off of the sand.
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Answer:
distance of 2nd team from 1st team will be: 58.2
Direction of 2nd team from 1st team will be: 14.90 deg North of east
Explanation:
ASSUME Vector is R and makes angle A with +x-axis,
therefore component of vector R is
From above relation
Assuming base camp as the origin, location of 1st team is
away at 21 deg North of west (North of west is in 2nd quadrant, So x is -ve and y is positive)
location of 2nd team is at
, at 38 deg East of North = 32 km, at 58 deg North of east (North of east is in 1st quadrant, So x and y both are +ve)
Now position of 2nd team with respect to 1st team will be given by:
Using above values:
distance of 2nd team from 1st team will be:
Direction of 2nd team from 1st team will be:
Direction = 14.90 deg North of east