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Sedbober [7]
3 years ago
6

In the article “Who Shaped our Behaviors? Peers or Parents?”, Judy Rich Harris suggests that __________ are the most influential

in forming children’s personalities. A. teachers B. parents C. peers D. doctors
Physics
2 answers:
Vesna [10]3 years ago
8 0

Answer:

It is C

Explanation:

Just took the test

Olegator [25]3 years ago
3 0
<span>In the article “Who Shaped our Behaviors? Peers or Parents?”, Judy Rich Harris suggests that C. peers are the most influential in forming children's personalities.
When a child is young, it is very impressionable and will follow other people's influence easily. Usually, that influence comes from other kids who can do something, and then your child will want to do the same thing. So peers are crucial when forming a personality at such a young age.</span>
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Answer:

the acceleration due to gravity, g of the cylinder is 9.81m/s2

Explanation:

since the cylinder is rolling down from a hill, the acceleration due to gravity of any object coming down from the atmosphere is always constant which is g=9.8m/s2 or approximately 10m/s2

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A charge q is at the point x = 5.0 m , y = 0. Write expressions for the unit vectors you would use in Coulomb's law if you were
Flauer [41]

Answer:

A) \^r = \^y

B) \^r = -\^x

C) \^r = -0.14\^x + 0.99\^y

Explanation:

Coulomb's Law is

\vec{F}_{ab} = K\frac{q_1q_2}{r^2}\^r

where r is the distance between the two point charges.

The question clearly asks the unit vector expressions of the force that q exerts on the other charge. So, we do not need to find the force, but only the distance vector, r, between charges, and then we can derive the unit vector pointing only the direction of the force.

A) \vec{r} = \vec{r}_b - \vec{r}_a = (5\^x + \^y) - (5\^x + 0) = \^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{\^y}{1} = \^y

B) \vec{r} = \vec{r}_b - \vec{r}_a = (0 + 0) - (5\^x + 0) = -5\^x\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-5\^x}{5} = -\^x

C) \vec{r} = \vec{r}_b - \vec{r}_a = (4.5\^x + 3.5\^y) - (5\^x + 0) = -0.5\^x + 3.5\^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-0.5\^x + 3.5\^y}{\sqrt{(0.5)^2+(3.5)^2}} = \frac{-0.5\^x + 3.5\^y}{3.53} = -0.14\^x + 0.99\^y

7 0
3 years ago
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velocity (v) =distance(s) ÷ time (t)

Explanation:

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