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notsponge [240]
2 years ago
14

Describe what bacteria are - their parts, how they can be good, how they can be bad, and the different types.

Chemistry
2 answers:
Elden [556K]2 years ago
4 0
<h3>HIIII, so.... </h3><h2> In all there are two different types of Bacteria good bacteria and bad bacteria, the good bacteria helps fight off diseases and other sickness the bad bacteria can make you sick. </h2>

I hope that was enough to answer your question!!!

<h3>Have a good day and I hope you pass all of your exams!!!!! <u><em><3</em></u> </h3>

solmaris [256]2 years ago
4 0
Bacteria are living micro organism they Can be good or bad depending on the type an example for a good bacteria is the bacteria that lives in your stomach it helps you digest food and then example for bad bacteria is a virus that can get you very sick bacteria
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Why does the moon and the earth have the same mass
Evgesh-ka [11]

Answer:

Moon rocks contain few volatile substances (e.g. water), which implies extra baking of the lunar surface relative to that of Earth. The relative abundance of oxygen isotopes on Earth and on the Moon are identical, which suggests that the Earth and Moon formed at the same distance from the Sun.

Explanation:

3 0
1 year ago
Read 2 more answers
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
2 years ago
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adelina 88 [10]

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8 0
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Identify the phase changes in the figure that are labeled a
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How are ionic bonds formed
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