Answer:
1.503 J
Explanation:
Work done in stretching a spring = 1/2ke²
W = 1/2ke²........................... Equation 1
Where W = work done, k = spring constant, e = extension.
Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.
Substitute into equation 1
W = 1/2(26)(0.34²)
W = 13(0.1156)
W = 1.503 J.
Hence the work done to stretch it an additional 0.12 m = 1.503 J
Answer:
H = 5 m
Explanation:
As the person leaves the slide horizontally so the time taken by the person to hit the water is given as
so we can find the vertical velocity by which person will hit the water using kinematics
now the speed of the person at the end of the slide is given as
now by energy conservation we can find the initial height
Answer:
(A) = 2.13 s
(B) = 0.47 Hz
(C) = 0.25 m
(D) = 0.74 m/s
Explanation:
number of oscillations (n) = 15
time (t) = 32 secs
start point (L1) = 13 cm = 0.13 m
End point (L2) = 63 cm = 0.63 m
(A) period = time / number of oscillation
= 32 / 15 = 2.13 s
(B) frequency = 1 / period
= 1 / 2.13 = 0.47 Hz
(C) Amplitude = 0.5 ( L2 - L1 )
= 0.5 ( 0.63 - 0.13 )
= 0.25 m
(D) max speed = (2π / T) x A
= (2π / 2.13) x 0.25
= 0.74 m/s
