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3 years ago

Can we make electromagnet with copper

Physics

2 answers:

777dan777 [17]3 years ago

8 0

Answer:

only if you take copper

Explanation:

Any electric current has an associated magnetic field, so a current-carrying conductor is an electromagnet, regardless of what material it is made. ... However, using copper alone will not make a strong electromagnet

Sonja [21]3 years ago

7 0

An electromagnet is a coil of wire with an electric current flowing through it.
When the wire is coiled around in a cylinder, we call this a solenoid. The solenoid becomes an electromagnet when a current flows through it.

Why use copper?

Copper is used because it has a low electrical resistance (see conducting properties). This means that it is easy for the current to flow through it. Also, copper wire can be easily shaped to make a coil

What's the field like?

When the current flows through the wire, it makes the coil into a magnet. We call this an electromagnet.
The field of the electromagnet is similar to the field of a bar magnet. The coil has a north pole at one end and a south pole at the other.

Remember, that we show the lines of force coming out of the north pole and going into the South Pole.

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A motorcycle rides on the vertical walls around the perimeter of a large circular room. The friction coefficient between the mot

igomit [66]

Answer:

option D

Explanation:

given,

coefficient of friction between wall and tire = µ

speed of motorcycle = s

friction force = f = μ N

where normal force will be equal to centripetal force

$N = \dfrac{mv^2}{r}$

for motorcycle to not to slip weight should equal to the centripetal force

now,

$m g =\mu \dfrac{mv^2}{r}$

$\mu =\dfrac{rg}{s^2}$

where "rg" is constant

$\mu\ \alpha \ \dfrac{1}{s^2}$

$\mu\ \alpha \ s^{-2}$

Hence, the correct answer is option D

7 0

3 years ago

Which of the following is NOT a type of model used in scientific inquiry? interactive, mathematical, conceptual, convergent

katrin2010 [14]

A conceptual model. Hope this helps.

5 0

3 years ago

Read 2 more answers

What is the potential difference between the plates of a 3.7-f capacitor that stores sufficient energy to operate a 75.0-w light

Elena L [17]

The potential difference between the plates will be 1552 Volts.

<h3>What is a potential difference?</h3>

Voltage, or the difference in electric potential between two points, is defined as the amount of labor per unit of charge needed to move a test charge between the two points.

Given that a 3.7-f capacitor that stores sufficient energy to operate a 75.0-w

The potential difference will be calculated by the formula below:-

Q = I t

Where I = charge / time

Q = V * C

V C = I t

V = I t / C

V = 75 C/s x 60 sec / 2.9 faraday

V = 1552 Volts

To know more about potential differences follow

brainly.com/question/25923373

#SPJ4

4 0

1 year ago

A car accelerates uniformly from rest to 20 m/sec in 5.6 sec along a level stretch of road. Ignoring friction, determine the ave

bonufazy [111]

Answer:

(a) $P=33000W$

(b) $P=51000W$

Explanation:

The average power is defined as the amount of work done during a time interval:

$P=\frac{W}{t}(1)$

According to work-energy theorem, the work done is equal to the change in kinetic energy. So, we have:

$W=\Delta K\\W=K_f-K_0\\W=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}\\(2)$

Recall that the weight is given by:

$w=mg\\m=\frac{w}{g}(3)$

The car accelerates uniformly from rest ( $v_0=0$ ). Replacing (3) in (2), we have:

$W=\frac{wv_f^2}{2g}$

(a) Finally, we replace this in (1):

$P=\frac{wv_f^2}{2gt}\\P=\frac{9000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=33000W$

(b)

$P=\frac{14000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=51000W$

3 0

4 years ago

ehidna [41]

Answer:

$a = -1.6\ m/s^2$

Explanation:

<u>Accelerated Motion</u>

It occurs when an object changes its speed over time. If the changes in speed are uniform, then the acceleration is constant, positive if the speed increases, negative if the speed decreases.

The acceleration is calculated as follows:

$\displaystyle a=\frac{v_f-v_o}{t}$

The aeroplane starts with a speed of vo=62 m/s and reaches a speed of vf=6 m/s in t=35 s.

The acceleration is:

$\displaystyle a=\frac{6-62}{35}=-\frac{56}{35}$

$\mathbf{a = -1.6\ m/s^2}$

3 0

3 years ago

Can we make electromagnet with copper​

Can we make electromagnet with copper