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Neko [114]
3 years ago
12

Can we make electromagnet with copper​

Physics
2 answers:
777dan777 [17]3 years ago
8 0

Answer:

only if you take copper

Explanation:

Any electric current has an associated magnetic field, so a current-carrying conductor is an electromagnet, regardless of what material it is made. ... However, using copper alone will not make a strong electromagnet

Sonja [21]3 years ago
7 0
An electromagnet is a coil of wire with an electric current flowing through it.
When the wire is coiled around in a cylinder, we call this a solenoid. The solenoid becomes an electromagnet when a current flows through it.


Why use copper?

Copper is used because it has a low electrical resistance (see conducting properties). This means that it is easy for the current to flow through it. Also, copper wire can be easily shaped to make a coil

What's the field like?

When the current flows through the wire, it makes the coil into a magnet. We call this an electromagnet.
The field of the electromagnet is similar to the field of a bar magnet. The coil has a north pole at one end and a south pole at the other.

Remember, that we show the lines of force coming out of the north pole and going into the South Pole.
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I’m not sure how to solve this
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Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

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