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Lerok [7]
3 years ago
14

which type of precipitation would likely be falling from cumulus clouds with a ground air temperature of 14 degree c .. A) snow.

B) sleet. C) rain. D) hail
Physics
1 answer:
seraphim [82]3 years ago
8 0

The type of precipitation that would likely be falling from cumulus clouds with a ground air temperature of 14 degree Celsius is rain. The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Assuming the speed of sound is 340 m/s, what is the most likely speed of the jet shown below?
inysia [295]

Well we know it has to be greater than 300,000 km/s since we can't see it.

We can't calculate it any closer than that using the given information.

7 0
3 years ago
In a liquid with a density of 1400 kg/m3 , longitudinal waves with a frequency of 370 Hz are found to have a wavelength of 8.40
VARVARA [1.3K]

Answer:

Bulk modulus = 1.35 × 10^{10} Pa

Explanation:

given data

density = 1400 kg/m³

frequency = 370 Hz

wavelength = 8.40 m

solution

we get here bulk modulus of the liquid that is

we know Bulk Modulus = v^2*\rho   ...............

here \rho is density i.e 1400 kg/m³

and v is =  frequency × wavelength

v = 370 × 8.40 = 3108 m/s

so here bulk modulus will be as

Bulk modulus = 3108² × 1400

Bulk modulus = 1.35 × 10^{10} Pa

3 0
3 years ago
Một khối khí hidro bị nén đến thể tích bằng 1/2 lúc đầu khi nhiệt độ không đổi. Nếu vận tốc trung bình của phân tử hidro lúc đầu
BartSMP [9]

answer: what language is this???

7 0
2 years ago
Light of wavelength 600 nm passes though two slits separated by 0.22mm and is observed on a screen 1.1m behind the slits. The lo
Ne4ueva [31]

Answer:

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

Explanation:

We have to take into account the expression for the position of the fringes

dsen\theta=m\lambda\\y=\frac{m\lambda D}{d}

where m is the number of the maximum, d is the separation of the slits, D is the distance to the screen.

(a) By replacing we obtain

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

(b)  more information is required to solve this point. Please complete the information.

HOPE THIS HELPS!

4 0
3 years ago
Read 2 more answers
Solar winds have an influence all the way to about 160 AU from the Sun. About how many kilometers is that?
Mumz [18]

Answer: A. 24,000,000,000 km

Explanation: An Astronomical Unit  commonly abbreviated as AU is the average distance between Earth and the Sun and is about 150 million kilometers.

Astronomical unit is mainly used to measure distances within our solar system.

1 AU is equal to  150\times 10^6 km

Thus 160 AU  is equal to \frac{150\times 10^6}{1}\times 160=24000\times 10^6km=24000000000km

4 0
2 years ago
Read 2 more answers
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