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AnnZ [28]
3 years ago
14

A 50 wt% ni–50 wt% cu alloy is slowly cooled from 1400°c to 1200°c:

Physics
1 answer:
g100num [7]3 years ago
6 0
This composition from Ni and Cu is called cupronickel.It is high in copper and silver in colour and highly resistant to corrosion, particularly seawater. Cooper nickel is used in the industry, in marine engineering . Melting point is 2254,73 F, which is 1234.85 Celsius. In this range of tempereature the cupronickel melts.
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If the third charge (–| q 3 |) is placed at point P, but not held fixed, it will experience a force and accelerate away from the
Mazyrski [523]

Complete Question

The complete question is shown on the first uploaded image

Answer:

A

The potential of this system is  U=6.75*10^{-7}J

B

The electric potential at point p is V_p= -900V

C

The work required is  W= 9*10^{-7}J

D

The speed of the charge is  v=600m/s

Explanation:

A sketch to explain the question is shown on the second uploaded image

Generally the potential energy for a system of two charges is mathematically represented as

            U = \frac{kq_1 q_2}{d}

where k is the electrostatic constant with a value of  k = 9*10^9 N m^2 /C^2

           q is the charge with a value of  q = 1*10^{-9}C

           d is the distance given as   d =5m

Now we are given that  q_1 = q and  q_2 = 3q and

Now substituting values

             U = \frac{9*10^9 *1*10^{-9} * 3*10^{-9}}{5}

                U=6.75*10^{-7}J

The electric potential at point P is mathematically obtained with the formula

             V_p = V_{-q} + V_{-3q}

I.e the potential at q_1 plus the potential at  q_2

Now potential at q_1 is mathematically represented as

                   V_{-q} = \frac{-kq}{s}

and the potential at q_2 is mathematically represented as

                        V_{-3q} = \frac{-3kq}{s}

Now substituting into formula for potential at  P

                  V_p = \frac{-kq}{s} + \frac{-3kq}{s}  = -\frac{4kq}{s}

                       = \frac{4*9*10^9 *1*10^{-9}}{4*10^{-2}}

                      V_p= -900V

The Workdone to bring the third negative charge is mathematically evaluated as

                W =\Delta U = \frac{kq_1q_3}{s} + \frac{kq_2q_3}{s}

                                 = \frac{kq*q}{s} +   \frac{kq*3q}{s}

                                = \frac{4kq^2}{s}

                               = \frac{4* 9*10^9 * (1*10^{-9})^2}{4*10^{-2}}

                              W= 9*10^{-7}J

From the Question are told that the charge q_3 would a force and an acceleration which implies that all its potential energy would be converted to kinetic energy.This can be mathematically  represented as

                   \Delta U = W = \frac{1}{2} m_{q_3} v^2

                         9*10^{-7} = \frac{1}{2} m_{q_3} v^2

Where m_{q_3} = 5.0*10^{-12}kg

Now making v the subject we have

                 v = \sqrt{\frac{9*10^{-12}}{5*10^{-12}*0.5} }

                     v=600m/s  

8 0
3 years ago
What is the relationship between the mass, velocity, and momentum of an object?
den301095 [7]
In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity. The equation<span> illustrates that momentum is directly </span>proportional<span> to an object's mass and directly </span>proportional<span> to the object's velocity.</span>
3 0
3 years ago
Read 2 more answers
A motor has a rotor (with armature) of moment of inertia ????m . The rotor is attached to a gear box of gear ratio G &gt; 1. The
Inessa [10]

Answer:

hello your question is incomplete attached below is the complete question

answer : The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor  i.e. J > Jm

Explanation:

Gear ratio G > 1

a) Determine the moment of inertia felt by the motor

moment of inertia felt by Motor = moment of Inertia at the armature

b) Determine the moment of inertial felt by someone who is rotating the mass by hand

moment of inertia felt by someone is = J

The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor

attached below is a detailed solution

3 0
3 years ago
A box with a mass of 50 kg is raised straight up. What is the force of the box?
8_murik_8 [283]

Answer:

A box with a mass of 50 kg is raised straight up. What is the force of the box? plss help!! two types exist-positive and negative. possible answers: A- electric current B- repel C- lines of force D- charges. Five wavelengths are generated every 0.100 s in a tank of water.

Explanation:

I hope it helped

3 0
2 years ago
What does it mean to say that momentum is conserved?
balu736 [363]
The momentum of two or more objects during collisions is not lost nor gained
8 0
3 years ago
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