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3 years ago

Why is an integrated circuit (IC) referred to as a special device?" points more than 10 plz help

Engineering

1 answer:

sladkih [1.3K]3 years ago

5 0

Answer:

Because IC microcomputers are smaller and more versatile than previous control mechanisms, they allow the equipment to respond to a wider range of input and produce a wider range of output. They can also be reprogrammed without having to redesign the control circuitry

Explanation:

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Some soil has a discharge rate of 0.1 L/s, an area of 11 m2, and a hydraulic head that is given empirically by the function H =

Artist 52 [7]

Answer:

3.03 * 10 ⁻⁴ m/s

Explanation:

see attached picture for explanation.

3 0

4 years ago

5x−2y=30 Complete the missing value in the solution to the equation. (8, )

givi [52]

Answer:

Value of y = 5

(8,5)

Explanation:

Given:

5x−2y=30

Value of x = 8

Find:

Value of y

Computation:

⇒ 5x−2y=30

⇒ 5(8)−2y=30

⇒ 40−2y=30

⇒ -2y = -10

y = 5

Value of y = 5

(8,5)

4 0

3 years ago

Disadvantages of bezier curve and b-spline

Gnesinka [82]

Answer:

The main disadvantage of the Bezier-curves is the global influence of the control points on the whole curve.

This has two major drawbacks: (1) every change of a control point (insert, move, delete) changes the look of the curve in all points of the curve, and (2) the computation time needed for a big set of control points is comparatively high. The reason is the weighting-function form.

hope it helps,pls mark me as brainliest

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3 years ago

The components of your sample mixture are present in trace amounts. Assuming that you will be using GC, what kind of sample intr

Oxana [17]

Answer:

Gas Chromatography (GC or GLC) is a commonly used analytic technique in many ... for quality control as well as identification and quantitation of compounds in a mixture. ... A broad variety of samples can be analyzed as long as the compounds are ... Most analytical gas chromatographs use capillary columns, where the ...

Explanation:

5 0

3 years ago

A soil has the following Green-Ampt parameters Effective porosity 0.400 Initial volumetric moisture content-15% Hydraulic Conduc

Rudik [331]

Answer:

The graphs are attached below

Explanation:

Ans) We know,

F(t) = K(t - to) + zΔ∅ ln[(1 + F(t)/zΔ∅]

where K = hydraulic conductivity =0.1 cm/hr

z = capillary suction =20cm

Δ∅ = ∅ (1 - Se)

∅ = effective porosity , Se = initial moisture content

Δ∅ = 0.40(1 - 0.15)

Δ∅ = 0.34

Now, F(t) = 0.1(t - to) + 20(0.34) ln[ 1 + F(t)/6.8]

F(t) = 0.1(t - to) + 6.8 ln [1+ 0.147 F(t)]

Also, infiltration rate (f),

f = K [(zΔ∅ + F)/F]

f = 0.40 [6.8 + F]/F

Condition of ponding,

Ponding time tp = K zΔ∅ i(i-k)

where, i = rainfall rate (1cm/hr)

tp = 0.40(6.8) / 0.60

tp= 4.53 hours

Now, cumulative infiltraton at ponding Fp = i tp

Fp = 1 x 4.53 or 4.53 cm

For infiltration at time less then ponding time , infiltration rate = rainfall rate

For t = 0.25 hr , f = 1cm/hr ; F = 0.25 x 1 = 0.25 cm

For t = 0.50 hr , f = 1cm/hr ; F = 0.50 cm

For t = 0.75 hr , f = 1cm/hr ; F = 0.75 cm

For t = 1 hr , f = 1cm/hr ; F = 1cm/hr

For t > tp ,

Equivalent time origin(to),

to = tp - 1/K [ Fp - z Δ∅ ln (1+ Fp/zΔ∅)

to = 4.53 - 1/0.40[ 4.53 - 6.8 ln(1 + 0.66)

to = 4.53 - 2.5 ( 4.53 - 3.44)

to = 1.82 hr

Hence,

F = 0.10( t - 1.82) + 6.8 ln[ 1+ 0.147F(t)]

Solving above equation for t by assuming F, and further solving equation for infiltration rate

Ans (a) Following is required curve :

O.S 1-5 2 time Chr)ホー Lt 2 time Chr)

Ans (c) Following is required table :

Ans (d) For time step t = 0.25 hrs

At t < tp ; i = f = 1 cm/hr

F = i x t

F = 1 x 0.25

F = 0.25 cm

5 0

4 years ago