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Citrus2011 [14]
3 years ago
6

Water flows through a nozzle at the end of a fire hose. If the nozzle exit velocity must be 20 m/s and the exit diameter is 40 m

m, determine the minimum flow rate that the pump must provide.
Engineering
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

minimum flow rate provided by pump is 0.02513 m^3/s

Explanation:

Given data:

Exit velocity of nozzle = 20m/s

Exit diameter = 40 mm

We know that flow rate Q is given as

Q = A \times V

where A is Area

A =\frac{\pi}{4} \times (40\times 10^{-3})^2 = 1.256\times 10^{-3} m^2

Q = 1.256\times 10^{-3} \times 20 = 0.02513 m^3/s

minimum flow rate provided by pump is 0.02513 m^3/s

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Air is to be compressed so that its volume is reduced to half of its original volume if the initial pressure is 200 kPa and the
Alex_Xolod [135]

Answer:

P_{2} = 527.803\,kPa

Explanation:

The politropic relationship for a isentropic process is:

\frac{P_{2}}{P_{1}} = \left(\frac{V_{1}}{V_{2}}  \right)^{\gamma}

Where \gamma is the ratio of specific heats

The final pressure is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}}\right)^{\gamma}

P_{2} = (200\,kPa)\cdot (2)^{1.4}

P_{2} = 527.803\,kPa

7 0
3 years ago
Air is pumped from a vacuum chamber until the pressure drops to 3 torr. If the air temperature at the end of the pumping process
malfutka [58]

Answer:

The final pressure is 3.16 torr

Solution:

As per the question:

The reduced pressure after drop in it, P' = 3 torr = 3\times 0.133\ kPa

At the end of pumping, temperature of air, T = 5^{\circ}C = 278 K

After the rise in the air temperature, T' = 20^{\circ}C = 293 K

Now, we know the ideal gas eqn:

PV = mRT

So

P = \frac{m}{V}RT

P = \rho_{a}RT          (1)

where

P = Pressure

V = Volume

\rho_{a} = air\ density

R = Rydberg's constant

T = Temperature

Using eqn (1):

P = \rho_{a}RT

\rho_{a} = \frac{P}{RT}

\rho_{a} = \frac{3 times 0.133\times 10^{3}}{0.287\times 278} = 0.005 kg/m^{3}

Now, at constant volume the final pressure, P' is given by:

\frac{P}{T} = \frac{P'}{T'}

P' = \frac{P}{T}\times T'

P' = \frac{3}{278}\times 293 = 3.16 torr

7 0
4 years ago
Which is the best description of power? A. the amount of kinetic energy lost during motion
cestrela7 [59]

Answer:

D. a measure of how fast a machine performs work​

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

Hence, the best description of power is that, it is a measure of how fast a machine performs work.

This can be calculated by using the mathematical expression below;

Power = \frac {Work done}{Time}

But we know that, Workdone = force * distance

6 0
3 years ago
Define engineer with work field​
Andrew [12]

Answer:

If you're talking about a field engineer then here is the basic description of their job.

Explanation:

They usually inspect and install equipment, direct workers, and report project status. They are in charge of making sure everything works smoothly. Engineers who work in the field oversee projects and are usually traveling.

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Ground effect is felt at a height that is equal to the plane's wingspan.<br> True or False
Oliga [24]

Answer:

True

Explanation:

7 0
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