Answer:
W = 12.8 KW
Explanation:
given data:
mass flow rate = 0.2 kg/s
Engine recieve heat from ground water at 95 degree ( 368 K) and reject that heat to atmosphere at 20 degree (293K)
we know that maximum possible efficiency is given as



rate of heat transfer is given as



Maximuim power is given as

W = 0.2038 * 62.7
W = 12.8 KW
Engineering ethics is not without abstraction, but in contrast with computing, it is animated by a robust and active movement concerned with the seamless identification of ethics with practice.
<h3 /><h3>What is engineering?</h3>
This is a branch of science and technology concerned with the design, building, and use of engines, machines, and structures that uses scientific principles.
Comparing ethics in engineering and ethics in computing:
- Engineering ethics are a set of rules and guidelines. While computing ethics deals with procedures, values and practices.
- In engineering ethics, engineers must adhere to these rules as a moral obligation to their profession While in computing ethics, the ethics govern the process of consuming computer technology.
- Following these ethics for the two professions will NOT cause damage, but disobeying them causes damage.
Some practical examples in the computing field:
- Avoid using the computer to harm other people such as creating a bomb or destroying other people's work.
- Users also should not use a computer for stealing activities like breaking into a bank or company.
- Make sure a copy of the software had been paid for by the users before it is used.
Some practical examples in the engineering field:
- Integrity for oneself.
- Respect for one another.
- Pursuit of excellence and accountability.
Hence, Engineering ethics is the field of system of moral principles that apply to the practice of engineering and following them is important to the profession.
Read more about <em>engineering</em> here:
brainly.com/question/17169621
#SPJ1
Answer:
hmmmm i think orange I may be wrong....
Explanation:
Answer:
401.3 kg/s
Explanation:
The power plant has an efficiency of 36%. This means 64% of the heat form the source (q1) will become waste heat. Of the waste heat, 85% will be taken away by water (qw).
qw = 0.85 * q2
q2 = 0.64 * q1
p = 0.36 * q1
q1 = p /0.36
q2 = 0.64/0.36 * p
qw = 0.85 *0.64/0.36 * p
qw = 0.85 *0.64/0.36 * 600 = 907 MW
In evaporation water becomes vapor absorbing heat without going to the boiling point (similar to how sweating takes heat from the human body)
The latent heat for the vaporization of water is:
SLH = 2.26 MJ/kg
So, to dissipate 907 MW
G = qw * SLH = 907 / 2.26 = 401.3 kg/s
<u>Answer:</u>
<u>of 150 pounds per square inch</u>
Explanation:
Note that the unit for measuring water pressure is called <u> pounds per square inch (psi)</u>
In the case of sprinklers and standpipe systems, a pressure <u>of 150 pounds per square inch</u> was used initially.