Answer:
0.0675 seconds
Explanation:
From the question,
We apply newton's second law of motion
F = m(v-u)/t.................... Equation 1
Where F = force exert by the brake, v = final speed, u = initial speed m = mass of the bicycle, t = time.
make t the subject of the equation
t = m(v-u)/F................... Equation 2
Given: m = 180 kg, u = 6.0 m/s, v = 0 m/s (comes to stop), F = -1600 N ( agianst the dirction of motion)
Substitute these value into equation 2
t = 180(0-6.0)/-1600
t = -1080/-1600
t = 0.0675 seconds.
Answer:
48kg
Explanation:
i could be wrong if i am srry
The concepts of force<span>, mass, and weight play critical roles. Newton's Laws of. Motion ... the person stops </span>pushing<span>? ... F </span>net<span> =10 N </span>2<span> N. = 8 N (to the right) a = F </span>net<span> m. = 8 N. 5 kg. =1.6 m s. </span>2<span> ... </span>Two equal forces<span> act on an </span>object<span> in the directions shown. </span>If<span> these ... </span>Two<span> connected carts </span>being accelerated by a force<span> F applied by.</span>
