Answer:
L = 1.11 x m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.
Explanation:
Solution:
Data Given:
Heat Energy = 52000 J
Dielectric Constant of the plastic Bag = 3.7 = K
Thickness = 2.6 x m =d
V = 610 volts
A = width x Length
width = 20 cm = 20 x m
Length = ?
So,
we know that,
U = 1/2 C Δ
U = 52000 J
C = ?
V = 610 volts'
So,
U = 1/2 C Δ
52000 J = (0.5) x (C) x ()
C = 0.28 F
And we also know that,
C =
E = 8.85 x
K = 3.7
A = 0.20 x L
d = 2.6 x m
Plugging in the values into the formula, we get:
0.28 =
Solving for L, we get:
L = 1.11 x m,
is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.
Her sister Judea would probably be willing to help her.
Answer:
27.6 m/s
5.64 s
Explanation:
Given:
Δy = 39 m
a = -9.8 m/s²
v = 0 m/s
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (39 m)
v₀ = 27.6 m/s
Find: 2t
Δy = vt − ½ at²
(39 m) = (0 m/s) t − ½ (-9.8 m/s²) t²
t = 2.82 s
2t = 5.64 s
Answer:
1. v = 6.67 m/s
2. d = 9.54 m
Explanation:
1. To find the horizontal velocity of the rock we need to use the following equation:
<u>Where</u>:
d: is the distance traveled by the rock
t: is the time
The time can be calculated as follows:
<u>Where:</u>
g: is gravity = 9.8 m/s²
Now, the horizontal velocity of the rock is:
Hence, the initial velocity required to barely reach the edge of the shell below you is 6.67 m/s.
2. To calculate the distance at which the projectile will land, first, we need to find the time:
So, the distance is:
Therefore, the projectile will land at 9.54 m of the second cliff.
I hope it helps you!
Answer:
Acceleration
Explanation:
Acceleration is the rate of change in velocity
speed is how fast an object is moving
Velocity is how fast an object is moving in the particular direction
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