Answer:
1. Distance, S = 26.58 meters
2. Acceleration of gravity, g = 58.60 m/s²
Explanation:
1. Given the following data;
Initial velocity = 4.66 m/s
Acceleration = 5.66 m/s²
Time = 2.35 seconds
To find the distance travelled by the object, we would use the second equation of motion;
S = ut + ½at²
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
S = 4.66*2.35 + ½*5.66*2.35²
S = 10.951 + (2.83 * 5.5225)
S = 10.951 + 15.629
S = 26.58 meters
2. Given the following data;
Displacement (height) = 1.55 m
Time, t = 0.23 seconds
To find the acceleration of gravity, we would use the following formula;
Height = ½gt²
Substituting into the formula, we have;
1.55 = ½ * g * 0.23²
1.55 = ½ * g * 0.0529
1.55 = 0.02645g
Acceleration of gravity, g = 1.55/0.02645
Acceleration of gravity, g = 58.60 m/s²
