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zepelin [54]
3 years ago
13

What is the energy of a photon of ultraviolet radiation with a frequency of 4.4 × 1015 Hz? Planck’s constant is 6.63 × 10–34

Physics
2 answers:
goblinko [34]3 years ago
6 0

Answer:

A. 2.9 × 10–18 J

Explanation:

Hunter-Best [27]3 years ago
4 0

Answer:

2.9\cdot 10^{-18} J

Explanation:

The energy of a photon is given by:

E=hf

where

h is the Planck constant

f is the frequency of the photon

In this problem, we have:

h = 6.63\cdot 10^{-34} Js

f=4.4\cdot 10^{15} Hz is the frequency of the photon

Substituting into the equation, we find:

E=(6.63\cdot 10^{-34} Js)(4.4\cdot 10^{15} Hz)=2.9\cdot 10^{-18} J

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