Answer:
electron-electron repulsion
Explanation:
When electrons add into valence shell of neutral elements, the element assumes a negative oxidation state. With this, the number of electrons having (-) charges will be larger than the number of protons having positive (+) charges. As a result, the extra electrons repel one another (i.e., like charges repel) and a larger radius is the result.
In contrast, when cations are formed, electrons are removed from the valence level (oxidation) producing an element having a greater number of protons than electrons. The larger number of protons will function to attract the electron cloud with a greater force that results in a contraction of atomic radius and a smaller spherical volume than the neutral unionized element.
To visualize, see attached chart that shows atomic and ionic radii before and after ionization of the elements.
<span>6CO</span>₂ +<span> 6H</span>₂O +<span> energy → C</span>₆H₁₂O₆<span> 6O</span>₂
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The molar volume of the gas : V = 447.993 L
<h3>Further explanation</h3>
Given
n = 1 mol
P = 0.05 atm
T = 273 K
Required
The molar volume
Solution
Ideal gas law :
PV=nRT
V = nRT/P
Input the value :
V = 1 x 0.08205 x 273 / 0.05
V = 447.993 L
Answer:
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