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3 years ago

Need help extra points and Mark as brainlist

Mathematics

1 answer:

Tanya [424]3 years ago

8 0

Answer:

Step-by-step explanation:

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9,000 + 40 + 0.1 + 0.008 I need to put it in standard form. Please help!

Andre45 [30]

Answer:

-12

Step-by-step explanation:

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4 years ago

Find SY and XY. PLEASE HELP ME IT IS DUE SOON IF YOU DONT KNOW DO NOT ANSWER

alina1380 [7]

Answer:

SY = 16

XY = 12

Step-by-step explanation:

15/20 = 12/SY

15SY = 240

SY = 16

15/20 = 9/XY

15XY = 180

XY = 12

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3 years ago

HELP!!! HURRY!!! NO SPAM!!!! Identify the translation of the figure with the vertices W(2,−3), X(5,−3), Y(5,−5) and Z(2,−5), alo

kakasveta [241]

Answer:

W - (-4,4)

X - (-1,4)

Y - (-1,2)

Z - (-4,2)

Step-by-step explanation:

hope it helps. :)

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3 years ago

I NEED HELP ASAP PLEASE GIVING BRAINLIEST!!

Salsk061 [2.6K]

Answer:

35 more video games

Step-by-step explanation:

40 times 3 and then substract 85

120-85=35

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3 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago