Answer:
2
Explanation:
It is going through the air and is moving so that means that it has kinetic energy. But it is also going to go the down, which gives it potential energy.
Answer:
Mass of barium sulfate = 8.17 g
Explanation:
Given data:
Mass of sodium sulfate = 4.98 g
Mass of barium sulfate produced = ?
Solution:
Na₂SO₄ + Ba(NO₃)₂ → BaSO₄ + 2NaNO₃
Moles of sodium sulfate:
Number of moles = mass/molar mass
Number of moles =4.98 g / 142.04 g/mol
Number of moles = 0.035 mol
Now we will compare the moles pf sodium sulfate and with barium sulfate.
Na₂SO₄ : BaSO₄
1 : 1
0.035 : 0.035
Mass of barium sulfate:
Mass = number of moles × molar mass
Mass = 0.035 mol ×233.4 g/mol
Mass = 8.17 g
Answer:
9.89 x 10²³ molecules H₂S
Explanation:
To find the molecules of H₂S, you need to (1) convert grams S to moles S (via the atomic mass of sulfur), then (2) convert moles S to moles H₂S (via the mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂S to molecules H₂S (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Atomic Mass (S): 32.065 g/mol
2 H₂S(s) + SO₂(g) -----> 3 S(s) + 2 H₂O(l)
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
79.0 g S 1 mole 2 moles H₂S 6.022 x 10²³ molecules
--------------- x --------------- x ---------------------- x ------------------------------------- =
32.065 g 3 moles S 1 mole
= 9.89 x 10²³ molecules H₂S
Answer:
Sample B
Explanation:
When heat is added to a substance, the molecules and atoms vibrate faster. Since the speed for Sample B is higher this means it has a higher temperature as well.
Answer:
D. Solution A has more concentrated acid than solution B and acid in solution A is also a weaker acid than that in solution B.
Explanation:
As it has been said in the question that the volume to reach the equivalence point of the solution A is twice the volume of solution B, this is because the acid in the solution A is more concentrated than B that's why more NaOH was required to reach to the equivalence point.
Since the pH at the equivalence point was greater for solution A that means the acid in solution A was a weak acid that's why the pH raised more as the NaOH was added to the solution.