The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.
Step-by-step explanation:
Given,
The distance traveled by plane = 1463 miles
The trip with the wind took 11 hours.
The trip took 19 hours against the wind.
Let,
s be the speed of plane and w be the speed of wind.
Therefore;
Speed with the wind = s+w
Speed into the wind = s-w
We know that;
Distance = Speed * Time
Therefore;
Equation for trip taken with wind.
1463 = 11(s+w)
Dividing both sides by 11

Equation for trip taken into the wind
1463 = 19(s-w)
Dividing both sides by 19

Adding Eqn 1 and 2

Dividing both sides by 2

Putting s=105 in Eqn 1

The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.
Answer:
2
Step-by-step explanation:
3 x 4 = 12 - 8 = 4 ÷ 2 = 2
This is a question that will require Pythagoras' theorem as you want to find the length of a diagonal of a triangle and are given the measurements of two sides. I have attached a picture of how to solve this problem.
To the nearest 10th of a foot, the answer is 77.6ft
Answer:
1 : 19 PM
Step-by-step explanation:
9 + 3 = 12
42 + 37 + 79
12:00 + 1 hour and 19 minutes
1 : 19 pm
E+(e-24)=126
2e-24=126
2e=150
e=75
So (s)he recieved 75 and 75-24=51 emails on those days.