Minerals are grouped according to their

A hot air balloon is filled with 1.31 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 121 ∘ C . Wha

victus00 [196]

Answer:

$1.82\times 10^6 L$ is the volume of the air in the balloon after it is heated.

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (at constant pressure)

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1= 1.31\times 10^6 L\\T_1=11^oC=(11+273.15)K=284.15K\\V_2=?\\T_2=121^oC=(121+273.15)K=394.15 K$

Putting values in above equation, we get:

$\frac{1.31\times 10^6 L}{284.15 K}=\frac{V_2}{394.14 K}\\\\V_2=\frac{V_1\times T_2}{T_1}$

$V_2=1.82\times 10^6 L$

$1.82\times 10^6 L$ is the volume of the air in the balloon after it is heated.

4 0

3 years ago

PLEASE ANSWER FAST

Elis [28]

First we need to calculate the number of moles of FeS $_{2}$ :

number of moles = mass (grams) / molecular mass (g/mol)

number of moles of FeS $_{2}$ = 198.2/120 = 1.65 moles

From the chemical reaction we deduce that:

if 4 moles of FeS $_{2}$ produces 8 moles of SO $_{2}$

then 1.65 moles of FeS $_{2}$ produces X moles of SO $_{2}$

X = (1.65×8)/4 = 3.3 moles of SO $_{2}$

Now we can calculate the mass of SO $_{2}$ :

mass (grams) = number of moles × molecular mass (grams/mole)

mass of SO $_{2}$ = 3.3×64 = 211.2 g

7 0

3 years ago

The balanced equation for the gaseous state oxidation of ammonia is shown below. 4 nh3 + 5 o2 → 4 no + 6 h2o how many moles of o

pychu [463]

Calculate the number of mole of 5O2:
1.2 x 5/4=1.5 mol

7 0

3 years ago

A chemist measures the energy change Delta H during the following

Ann [662]

Answer: 1) endothernic

2) Yes absorbed

Explanation:

Decomposition is a chemical reaction in which one reactant gives two or more than two products. All decomposition reactions are endothermic reactions as energy is absorbed to break the bonds.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and $\Delta H$ for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and $\Delta H$ for the reaction comes out to be negative.

5 0

2 years ago

An 1.04-L sample of gas at 759 mm Hg pressure

telo118 [61]

PV = nRT

where P is the pressure,

V is the volume,

n is the moles of gas,

R is the gas constant,

and T is the temperature.

We must relate this equation to a sample of gas at two different volumes however. Looking at the equation, we can relate the change in volume by:

P1V1 = P2V2

where P1 is the initial pressure,

V1 is the initial volume,

P2 is the final pressure,

and V2 is the final volume.

Looking at this relationship, pressure and volume have an indirect relationship; when one goes up, the other goes down. In that case, we can use this equation to solve for the new pressure.

P1V1 = P2V2

(759 mm Hg)(1.04 L) = P2(2.24 L)

P2 = 352 mm Hg (rounded to three significant figures)

8 0

3 years ago