Answer: To determine the mole ratio
Explanation:
A balanced chemical equation is needed ,because it helps to determine the mole ratio of acid and base.
The mole ratio ensures that the number of moles of H+ provided by the acid is equal to number of moles of OH- ion provided by the base, For neutralization to occur, this must be the case.
<span>ppm = mg/L
or
Kg solution
Mass % = Mass of Solute/Mass of solution
0.0390 M = x moles/1L
x = 0.0390 Moles of F-
0.0390 mol x 18.998403 g/mol = 0.7409 g
PPM:
1mg = 1000g
0.7409g = 740.9mg
740.9mg/1L = 740.9mg
Mass Percent:
density 1 g/mL
thus
1 g = 1 mL
thus
1 L = 1 kg
thus
1 L = 1000 g
so,
(0.7409 g/1000 g)*100
= 0.07409% (m/m)</span>
Answer:
0.98 g of H₂
Explanation:
the balanced equation for the reaction is
Mg + 2HCl ---> MgCl₂ + H₂
molar ratio of Mg to H₂ is 1:1
number of Mg moles reacted = 12 g/ 24.3 g/mol = 0.49 mol
according to molar ratio
when 1 mol of Mg reacts 1 mol of H₂ is formed
therefore when 0.49 mol of Mg reacts - 0.49 mol of H₂ forms
therefore mass of H₂ formed = 0.49 mol x 2 g/mol = 0.98 g
mass of H₂ formed is 0.98 g
Answer:
Percentage mass of Tin = 96.3%
Percentage mass of oxygen = 6.40%
Explanation:
The product of the reaction is an oxide of tin.
Assuming all of the 0.500 g sample of tin reacted with oxygen to produce the oxide:
Mass of oxide = 0.534 g
Mass of tin present in the oxide = 0.500 g
Mass of oxygen in the oxide = 0.534 g of oxide - 0.500 g Sn = 0.034 g O
Percentage composition = mass of element/mass of compound × 100%
Percentage composition of Sn = 0.500 g/0.534 g × 100 = 93.6% Sn
Percentage composition of oxygen = 0.034 g/0.534 g × 100 = 6.40%