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Mice21 [21]
3 years ago
7

Please help me with this homework

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0
I disagree. The first one is false. No exponent rules apply if the bases AND the exponents are different.

The second one is true. Bases are the sane so you add exponents. You get 3 to the -5 power. Written with positive exponents it’s 1/3 to the 5.
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The set of integers between -4 and 2?
mote1985 [20]
-3,-2,-1,0,1 are all between -4 and 2 excluding those numbers.

3 0
3 years ago
Brainliest + Points!
AysviL [449]
I believe the correct answer would be B. Down payment

Your welcome
5 0
3 years ago
5 times 7/10 <br><br> The product lies between - and -
svp [43]

Answer:

5 x 7/10 is equal to 3.5, therefore it lies between the whole numbers of 3 and 4.

3 0
4 years ago
Find the Perimeter of Polygon JKLMN. Round to the tenth.
kramer

9514 1404 393

Answer:

  24.1 units

Step-by-step explanation:

This is done using the Pythagorean theorem (or distance formula) to find the lengths of the sides.

For each side of the figure (except the bottom horizontal), you need to identify the dimensions of the right triangle whose hypotenuse is the side of interest. For example, LM is the hypotenuse of a triangle 4 units high and 1 unit wide. The Pythagorean theorem tells you LM has a length of ...

  LM = √(4^2 +1^2) = √17 ≈ 4.12

Similarly ...

  KL = √(2^2 +2^2) = √8 ≈ 2.83

  JK = √(1^2 +6^2) = √37 ≈ 6.08

  NJ = √(5^2 +1^2) = √26 ≈ 5.10

Of course, the length of MN is found by finding the difference of the x-coordinates:

  MN = 3 -(-3) = 6

Then the perimeter is the sum of side lengths:

  4.12 +2.83 +6.08 +5.10 +6.00 = 23.17 ≈ 24.1 . . . units

8 0
3 years ago
3. 1/4 added by 2. 5/6 estimated by each sum or difference
maxonik [38]

let's firstly convert the mixed fractions to improper fractions, and then add.


\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{2\frac{5}{6}}\implies \cfrac{2\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{17}{6}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{17}{6}\implies \stackrel{\textit{we'll use the LCD of 12}}{\cfrac{(3)13~~+~~(2)17}{12}}\implies \cfrac{39+34}{12}\implies \cfrac{73}{12}\implies 6\frac{1}{12}

3 0
3 years ago
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