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Gwar [14]
3 years ago
9

I will give you Brainly if you awsers correct if your just gonna awser for point pl just put I don’t know thanks

Chemistry
1 answer:
Ulleksa [173]3 years ago
8 0
Huhhhhhhhhhhhhhhhhhhhhhhhhh
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Which image exclusively represents the principle of radiation? A) IV B) III C) II D) I
arsen [322]

The principle of radiation protection is to trigger deterministic and stochastic effect.

Explanation:

The main aim of principle of radiation is to prevent the deterministic effects of radiation and reduce the risks of stochastic effects.

There are three general principals of radiation used for dealing with ionising radiation are Justification, Dose limitation and Optimization.

The three basic radiation principles are time, distance and shielding.

The risk of exposure to radiation is measured using the conventional unit rem or SI unit (sievert).

4 0
3 years ago
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Which type of change, chemical or physical, is a change on the atomic level?
zavuch27 [327]

Explanation:

Examples of chemical changes include, rusting, fire, and overcooking. Nuclear changes occur when the nuclei of atoms are rearranged to form new atoms. Examples of nuclear changes include atomic fission, nuclear fusion, and the energy of sun and stars.

3 0
3 years ago
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One of the main advantages of Hydrogen as a fuel is that:
weqwewe [10]

Answer:

The correct answer is option D.

Explanation:

A fuel cell is defined as the electrochemical cell which converts the chemical energy of a fuel (often used hydrogen) and an oxidizing agent (often used oxygen) into electrical energy via a pair of redox reactions.

The reactions which occur in hydrogen-oxygen fuel cell are:

At cathode:  H_2+2OH^-\rightarrow 2H_2O+2e^-

At anode:  \frac{1}{2}O_2+H_2O+2e^-\rightarrow 2OH^-

As we can see that reaction of hydrogen gas with oxygen gas gives us the water as a product which can be used for other things and it also doesn't pollutes environment.

6 0
4 years ago
Which fraction of a Sr-20 sample remains unchanged after 87.3 years?
stiks02 [169]
First off there are some issues in your questions but I can still help in answering this type of problem. First, there is no Sr-20. The 4 abundant form includes Sr-84, Sr-88, Sr-87, Sr-86, Sr-84. 
More importantly, the half life of strontium must be given. 

For demonstration sake, let us assume Sr-85 is the isotope. It has a half-life of 64.853 days and I'm assuming the units of 87.3 is in days. 

A/Ao = e^-(ln2/t)T

where A- final amount Ao -initial amount t- halflife T-total time elapsed

% = <span>e^-(ln2/64.853)(87.3) = 0.3933 or 39.33%
</span><span>
</span>
3 0
3 years ago
It takes 45.0 J to raise the temperature of an 8.10 g piece of unknown metal from 13.0∘C to 24.3 ∘C. What is the specific heat f
hodyreva [135]

Answer:

0.492 J/g °C

General Formulas and Concepts:

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J0
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • <em>ΔT</em> is change in temperature (in °C)

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>q</em> = 45.0 J

[Given] <em>m</em> = 8.10 g

[Given] <em>ΔT</em> = 24.3 °C - 13.0 °C = 11.3 °C

[Solve] <em>c</em>

<em />

<u>Step 2: Solve for </u><em><u>c</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                             45.0 J = (8.10 g)c(11.3 °C)
  2. Multiply:                                                                                                             45.0 J = (91.53 g °C)c
  3. Isolate <em>c</em>:                                                                                                            0.491642 J/g °C = c
  4. Rewrite:                                                                                                             c = 0.491642 J/g °C

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.491642 J/g °C ≈ 0.492 J/g °C

5 0
3 years ago
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