The answer above is correct (I took a test on this)
Answer:
3 HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃
Explanation:
An acid reacts with a base producing water and a salt. Having this in mind the reaction of nitric acid (HNO₃) and Iron (III) hydroxide (Fe(OH)₃) is:
HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃
<em>The H⁺ of the acid reacts with the OH⁻ to produce H₂O. The other ions (Fe³⁺ and NO₃⁻) produce the salt</em>
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There are 3 nitrates in products. To balance the nitrates:
<h3>3 HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃</h3>
<em>And this is the balanced reaction</em>
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Answer:
0.37 %
Explanation:
Given that:
Calculated density of aluminum = 2.69 g/cm³
Accepted density of aluminum = 2.70 g/cm³
Thus, applying values as:
<u>Percent error = 0.37 %</u>
Answer:
the initial temperature of the iron sample is Ti = 90,36 °C
Explanation:
Assuming the calorimeter has no heat loss to the surroundings:
Q w + Q iron = 0
Also when the T stops changing means an equilibrium has been reached and therefore, in that moment, the temperature of the water is the same that the iron ( final temperature of water= final temperature of iron = T )
Assuming Q= m*c*( T- Tir)
mc*cc*(T-Tc)+mir*cir*(T - Tir) = 0
Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )
Tir = 90.36 °C
Note :
- The specific heat capacity of water is assumed 1 cal/g°C = 4.186 J/g°C
- We assume no reaction between iron and water
Using PV = nRT, we can calculate the moles of the sample.
874 mmHg = 116,524 Pa
n = PV/RT
n = 116,524 x 294 x 10⁻⁶ / 8.314 x (140 + 273)
n = 9.98 x 10⁻³ mol
moles = mass / Mr
Mr = 0.271/9.98 x 10⁻³
Mr = 27.2
Mass of empirical formula = 14
Repeat units = 27.2 / 14 ≈ 2
Formula of substance:
C₂H₄
Combustion equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
1 mole produces 2 moles of CO₂, so 3 moles will produce 6 moles CO₂
