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lesantik [10]
3 years ago
11

A line in the lyman series of hydrogen has a wavelength of 122 nm. from what state did the electron originate?

Chemistry
1 answer:
ra1l [238]3 years ago
4 0
Lyman series is when the electron transitions from n≥2 to n=1. So, for the Lyman series, the Rydberg formula becomes

1/λ = R(1 - 1/n²)
where λ is the wavelength and R is the Rydberg constant for hydrogen (0.010972 nm⁻¹)

1/122 = 0.010972(1 - 1/n²)
Solving for n,
n = 1.988≈2

<em>Thus, the electron originated from the 2nd energy level.</em>
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Given a balanced chemical equation, number of moles of reactants, find mass of a product produced or given the mass of product f
Lina20 [59]
I can help you but what is the question here?
5 0
3 years ago
2 NH3 + 3 CuO --&gt; 3 Cu + N2 + 3 H2O
Gnom [1K]

<u>Answer:</u> 0.5 moles of N_2 are produced in the reaction

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of CuO = 113.6 g

Molar mass of CuO = 79.5 g/mol

Plugging values in equation 1:

\text{Moles of CuO}=\frac{113.6g}{79.5g/mol}=1.43 mol

For the given chemical reaction:

2NH_3+3CuO\rightarrow 3Cu+N_2+3H_2O

By the stoichiometry of the reaction:

If 3 moles of CuO produces 1 mole of N_2

So, 1.43 moles of CuO will produce = \frac{1}{3}\times 1.43=0.476=0.5mol of N_2

Hence, 0.5 moles of N_2 are produced in the reaction

5 0
3 years ago
A 0.2 M carboxylic acid (RCOOH) has a Ka = 1.66x10-6. What is the pH of this solution? Enter to 2 decimal places.
maria [59]

Answer:

3.24

Explanation:

The dissociation equation for the carboxylic acid can be represented as follows:

RCOOH —-> RCOO- + H+

We can use an ICE table to get the value of the concentration of the hydrogen ion. ICE stands for initial, change and equilibrium.

RCOOH RCOO- H+

Initial 0.2 0.0. 0.0

Change -x +x. +x

Equilibrium 0.2-x. x. x

We can now find the value of x as follows:

Ka = [RCOO-][H+]/[RCOOH]

(1.66* 10^-6) = (x * x)/(0.2-x)

(1.66 * 10^-6) (0.2-x) = x^2

x^2 = (3.32* 10^-7) - (1.66*10^-6)x

x^2 + (1.66 * 10^-6)x - (3.32* 10^-7) = 0

Solving the quadratic equation to get x:

x = 0.0005753650094369094 or - 0.0005753650094369094

As concentration cannot be negative, we discard the negative answer

Hence [H+] = 0.0005753650094369094

By definition, pH = -log[H+]

pH = -log(0.0005753650094369094)

pH = 3.24

8 0
3 years ago
What is the number of moles of solute in 250 mL of a .80M solution
Illusion [34]

Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution

Explanation:

because it is

8 0
3 years ago
If the valence electrons were removed, what would be the ion charge of the element?
Marizza181 [45]
The ion charge of this element, Na would be + 1, as a single valence electron has been removed and transferred to another atom, resulting in an atom with a greater number of protons than electrons, making it positively charged.
3 0
3 years ago
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