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sammy [17]
3 years ago
5

Can someone plz help me with this one problem plz!!!!

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

<u>x  |  y</u>

3  |  0

4  |  1

5  |  2

6  |  3

Step-by-step explanation:

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What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

5 0
3 years ago
How is this equation completed? I cannot find any examples in the book.
djverab [1.8K]

Answer: Option D

t_{max} =19\ s

Step-by-step explanation:

Note that the projectile height as a function of time is given by the quadratic equation

h = -12t ^ 2 + 456t

To find the maximum height of the projectile we must find the maximum value of the quadratic function.

By definition the maximum value of a quadratic equation of the form

at ^ 2 + bt + c is located on the vertex of the parabola:

t_{max}= -\frac{b}{2a}

Where a

In this case the equation is: h = -12t ^ 2 + 456t

Then

a=-12\\b=456\\c=0

So:

t_{max} = -\frac{456}{2*(-12)}

t_{max} =19\ s

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3 years ago
What is mean by probability ​
elena-14-01-66 [18.8K]

it is the chances of something to happen

4 0
3 years ago
Read 2 more answers
Solve using factoring
jolli1 [7]
The equation is balanced by the 3's on both sides so that cancels out. we are left with:
x^2-6x=0
we take out an x, leaving us with:
x(x-6)=0
we know that to find the solution [ or "zero's", ] we must set "x"=0, and "x-6"=0.
the solutions are: x=0 and 6.
hope that helped, xx
7 0
3 years ago
What is the range of the data below<br> 23,33,25,16,27,43,29,40,35
melomori [17]

Answer: 12

Step-by-step explanation: 35 - 23

7 0
3 years ago
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