Lets say the base is x and the height is y. The new base would be 1.2x and the new height would be 1.3y
Area of a triangle is base times height divided by 2:
1.2x*1.3y/2 = (1.2*1.3 + x*y)/2 = 1.56xy/2 = 0.78xy = 78% of xy
But a normal area would be 50% of xy
78% - 50% = 38%
ANSWER: 38% increase
First, we need to make the equation given to be in the form;
y=mx + b
where m is the slope and b is the intercept
8y - 3x = -8
Add 2x to both-side of the equation
8y = 3x - 8
Divide through the equation by 8
y = 3/8 x -1
comparing the above with y =mx + b
m = 3/8
slope of parallel equations are equal
From the options given the only equation with slope 3/8 is;
y= 3/8 x + 8
The above equation of the line is parallel to 8y - 3x = -8
Answer:
True
Step-by-step explanation:
0 . 0 0 0
whole Tenths Hundredths Thousandths
Lines are in the form y=mx+b, where m is the slope and b is the y-intercept. This line is thus y=9/4x-14, so C is correct. Multiplying by four, we get 4y=9x-56. Adding 56 and subtracting 4y, we see that 9x-4y=56, and multiplying by -1, we get 4y-9x=-56, so A is also correct. At this point, it is clear that B and D are incorrect, so A and C only are correct.
I’m not sure what your teacher wants you to do but I would do 110-50=60
