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Mila [183]
3 years ago
15

Sole w - 12 = -3 using mental math

Mathematics
2 answers:
kotykmax [81]3 years ago
3 0

Answer:

-15

Step-by-step explanation:

den301095 [7]3 years ago
3 0

Answer:

w=9

Step-by-step explanation:

w - 12 = -3

w-12+12=-3+12

w=9

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The Mayors of two small towns that adjoin a large community have engaged in an argument on which of their cities is safer, with
Lelu [443]

Answer:

1. City A: 150 violent crimes per 100,000 residents.

   City B: 161 violent crimes per 100,000 residents.

2. City A

Step-by-step explanation:

City A:

Population = 123,000

Violent crimes = 185

Violent crimes per 100,000 people:

V_{100k} = \frac{185*100,000}{123,000} \\V_{100k} = 150

City B:

Population = 84,000

Violent crimes = 135

Violent crimes per 100,000 people:

V_{100k} = \frac{135*100,000}{84,000} \\V_{100k} = 161

1. City A: 150 violent crimes per 100,000 residents.

   City B: 161 violent crimes per 100,000 residents.

2. Even though it has a bigger number of crimes, City A has the lowest crime rate since its population is larger.

5 0
3 years ago
Fifty tickets are sold for a raffle.you buy four tickets and your friend buys three tickets.one ticket is randomly chosen as the
Law Incorporation [45]

there would be a 14 percent chance of you or your friend winning

8 0
3 years ago
Read 2 more answers
Y = 4x + 3
Igoryamba
D) perpendicular!
A perpendicular's definition is: a straight line at an angle of 90° to a given line, plane, or surface.
And if you mark them on a graph you could see these two are opposite of each other.
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3 years ago
Read 2 more answers
(6t^4-t+1) - (6t^3-4t)
goldenfox [79]

Answer:

= 6 {t}^{4}   - 6 {t}^{3}  + 3t + 1

Step-by-step explanation:

6 {t}^{4}  - t + 1 - 6 {t}^{3}  + 4t \\  = 6 {t}^{4}   - 6 {t}^{3}  + 3t + 1

5 0
3 years ago
Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
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