1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mila [183]
2 years ago
15

Sole w - 12 = -3 using mental math

Mathematics
2 answers:
kotykmax [81]2 years ago
3 0

Answer:

-15

Step-by-step explanation:

den301095 [7]2 years ago
3 0

Answer:

w=9

Step-by-step explanation:

w - 12 = -3

w-12+12=-3+12

w=9

You might be interested in
WILL MARK BRAINLIEST! What is the formula to calculate the slope? Is it y^2-y^1/x^2-x^1? Please type it in for me.
Leya [2.2K]

Answer:

You are correct. Remember: rise over run.

m = \frac{y2-y1}{x2-x1}

6 0
3 years ago
Read 2 more answers
Built around 2600 BCE, the Great Pyramid of Giza in Egypt is 485 ft high (due to erosion, its current height is slightly less) a
Morgarella [4.7K]

Answer:1.69*10^12 J

Step-by-step explanation:

From figure above, using triangle ratio

485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485

Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3

Force slice = 150*755.5^2.y^2.∆y/485^2

From figure 2 in the attachment work done for elementary sclice

Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2

= (150*755.5^2*y^2)(485-y)∆y/485

To calculate the total work we integrate from y=0 to y= 485

Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485

Integrating the above

W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485

W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)

Work done 1.69*10^12joules

7 0
3 years ago
Select all the values that are equivalent to the given expression. Express your answer in scientific notation.
Anna35 [415]

Answer:

the first and last ones

Step-by-step explanation:

5 0
2 years ago
5. Choose the fragment which best completes the following sentence. Finance charges on a credit card Include (2 points)
lisabon 2012 [21]

Finance charges on a credit card Include "all of the above".

<u>Option: D</u>

<u>Explanation:</u>

Practically, a finance charge is any expense shown in the borrowing money costs, such as accrued interest and loan fees, including transaction fees. Finance charges are usually synonymous with "interest charges" even though they may contain late fees or other costs in some situations.

With credit cards, the interest that has accrued over the amount one owe throughout that particular billing cycle is an individual's finance fee. For every day of the month, the regular balance approach sums up an individual's financing fee. One need to know the precise credit card balance every day of the billing cycle to do that estimate correctly.

7 0
3 years ago
X-coordinate the definition for that
Step2247 [10]

Answer:

An x-coordinate is the x value in an ordered pair, which is just two mathematical objects, such as numbers, paired together. Usually, the x-coordinate is the first number in that pair. For instance, in the ordered pair (2,5), the x-coordinate would be '2.

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • Alicia borrowed $
    11·1 answer
  • Choose the fraction that has not been reduced to simplest form.
    12·2 answers
  • What is the perimeter of a rectangle?
    7·2 answers
  • Your poor health causes you to miss one work day every two weeks. You do not get paid when you are out sick. You normally work 8
    13·1 answer
  • | What is the square root of -16?
    6·1 answer
  • - write 30% as a rate per 100.
    13·1 answer
  • What is the volume of a volleyball with a diameter of 8 inches
    9·1 answer
  • How do you solve that (2cosx+1)(2cosx-1)(2cos2x-1)=2cos4x+1<br>Please help it's urgent!
    6·2 answers
  • Which two statements are true about triangle b?
    11·1 answer
  • Which of the following sets of ordered pairs represents a function?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!