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muminat
3 years ago
5

What is the area of the regular trapezoid below? - 6 cm T 8 cm 10 cm

Mathematics
1 answer:
Elenna [48]3 years ago
5 0

Answer:

Area = 64 cm²

Step-by-step explanation:

To find the area, we have to follow some steps:

=> <u>Step 1: Make the bases similar:</u>

Since we have 2 bases given 6 and 10 we have to come up with a third base by finding their average:

(6 + 10) / 2

(16) / 2

8

So now that we know our base,

=><u> Our second step is to multiply the base we found by the height of the trapezoid:</u>

Area = common base * height

Area = 8 * 8

Area = 64 cm²

Hope this helps!

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3 years ago
Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38
Katyanochek1 [597]
To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the 

First, we will need to find the slope of this equation. To find this, we must simplify the equation 3x+5y=38 into y=mx+b form. Lets do it!

3x+5y=38
= 5y = -3x+38 (Subtract 3x from both sides)
= y= -\frac{3}{5}x+ \frac{38}{5} (Divide both sides by 5) 

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is \frac{5}{3}. 

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

\frac{y-y _{1} }{x- x_{1} }=m

Substituting values, we find that:

\frac{y-4}{x-6}= \frac{5}{3}

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that: 

y= \frac{5}{3}x-6 , which is our final answer.

Thank you, and I wish you luck.
8 0
4 years ago
Read 2 more answers
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