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jeka57 [31]
3 years ago
9

Which of these is an example of an elastic collision? A. The cue ball crashing into the eight balls on a pool table. B. Two cars

colliding in an accident and moving together in the end. C. A kid landing a flip on a trampoline.
Physics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

The cue ball crashing into the eight balls on a pool table.

Explanation:

Elastic and inelastic collisions are two types of collisions.

For elastic collision, both the momentum and the kinetic energy before and after the collision remains conserved.

Out of the given options, the option that shows an example of an elastic collision is option A " The cue ball crashing into the eight balls on a pool table." All the eight balls after crashing moves with different velocity.

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Christina drives his moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. What distance did she cove
Mashutka [201]

Answer:

She covers the distance is 12 km.

The magnitude of displacement is 8.6 km.

The direction of her displacement is north east.

Explanation:

Given that,

Christina drives his moped 7 kilometers North and stop for lunch and then drive 5 km east.

We need to calculate the total distance

Using formula of distance

d=d_{1}+d_{2}

Put the value into the formula

d=7+5

d=12\ km

We need to calculate the magnitude of displacement

Using formula of displacement

D=xi+yj

D=5i+7j

D=\sqrt{5^2+7^2}

D= 8.6\ km

The direction of her displacement is north east.

Hence, She covers the distance is 12 km.

The magnitude of displacement is 8.6 km.

The direction of her displacement is north east.

6 0
3 years ago
Why can't you hear a sound in space ?
Anastaziya [24]

Answer:

As the vibrations of the particles reach your ear, your ear drum receives the vibrations which the brain then interprets as sound. In the vacuum of space, there are no (or very, very few) particles to vibrate, so sound cannot travel through this medium.

Explanation:

5 0
2 years ago
How does what happens to the particles in a substance during melting differ from what happens during freezing?
sasho [114]
When in the melting process particles start to move more freely when in the freezing process particles tend to slow and vibrate in place
8 0
3 years ago
A 5.00 kg pendulum swings back and forth. At the top of its arc it reaches a height of 0.36 m. What is the velocity of the pendu
azamat

Answer:

Gravitational potential energy = (mass) x (gravity) x (height)

Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²

When the pendulum is at the top of its swing, its potential energy is

(mass) x (gravity) x (height)

= (5 kg) x (9.8 m/s²) x (0.36 m)

= (5 x 9.8 x 0.36) joules

17.64 joules .

Energy is conserved ... it doesn't appear or disappear ... so that number is exactly the kinetic energy the pendulum has at the bottom of the swing, only now, it's kinetic energy:

17.64 joules = (1/2) x (mass) x (speed)²

17.64 joules = (1/2) x (5 kg) x (speed)²

Divide each side by 2.5 kg:

17.64 joules / 2.5 kg = speed²

Write out the units of joules:

17.64 kg-m²/s² / 2.5 kg = speed²

(17.64 / 2.5) (m²/s²) = speed²

7.056 m²/s² = speed²

Take the square root of each side: Speed = √(7.056 m²/s²) = 2.656 m/s.

Looking through the choices, we're overjoyed to see that one if them is ' 2.7 m/s '. Surely that's IT !

Hope this will help you ...

8 0
3 years ago
A straight segment of wire has a length of 25 cm and carries a current of 5A. If the wire is perpendicular to the magnetic field
Irina-Kira [14]

Answer:

The magnitude of the magnetic force acting on the conductor is 0.75 Newton

Explanation:

The parameters given in the question are;

The length of the straight segment of wire, L = 25 cm = 0.25 m

The current carried in the wire, I = 5 A

The orientation of the wire with the magnetic field = Perpendicular

The strength of the magnetic field in which the wire is located, B = 0.60 T

The magnetic force, 'F', is given by the following formula;

F = \underset{I}{\rightarrow }·L×\underset{B}{\rightarrow } = I·L·B·sin(θ)

Where;

\underset{I}{\rightarrow } = The current flowing, I

L = The length of the wire

\underset{B}{\rightarrow } = The magnetic field strength, B

θ = The angle of inclination of the conductor to the magnetic field

Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;

F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N

Therefore

The magnitude of the magnetic force, F = 0.75 N.

3 0
3 years ago
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