2 years ago

What name is given to the force on an object caused by Earth's gravitational pull?

Physics

1 answer:

egoroff_w [7]2 years ago

3 0

Answer:

gravity

Explanation:

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You’ve made the finals of the science Olympics. As one of your tasks you’re given 1.0 g of copper and asked to make a cylindrica

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Length = 2.92 m

Diameter = 0.11 mm

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We have $m = dl D \ \ \& \ \ \ R = \frac{\rho l}{A}$ , where:

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$m = 1.0 g = 1 \times 10^{-3} \ kg\\R = 1.3 \ \Omega\\\rho = 1.7 \times 10^{-8} \Omega m\\d = 8.96 \ g/cm^3 = 8960 kg/m^3$

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$\frac{m}{R} = \frac{d A^2}{\rho}$

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Using this Area, we find the diameter of the wire:

$D = \sqrt{\frac{4A}{\pi}}$

$D = \sqrt{\frac{4 \times 3.8 \times 10^{-8} }{\pi}}$

$D = 0.00011 \ m = 1.1 \times 10^ {-4} = 0.11 \ mm$

To find the length, we multiply the two equations stated initially:

$mR = d\rho l^2\\\\l^2 = \frac{mR}{d\rho} \\\l^2 = \frac {1.0 \times 10^{-3} \times 1.3}{8960 \times 1.7\times 10^{-8}}$

$l^2 = 8.534\\l = 2.92 \ m$

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What name is given to the force on an object caused by Earth's gravitational pull?​

What name is given to the force on an object caused by Earth's gravitational pull?