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3 years ago

III. For the following four sections: If you are given the formula, name the

Chemistry

1 answer:

serious [3.7K]3 years ago

5 0

Answer:

15.Potassium oxide

16.Calcium chloride

17.Aluminium sulphide

18.CaS

Explanation:

15.K is the chemical symbol of Potassium and generally the name of the non-metal at the end of a formula has the suffix '-ide' and since O is oxygen, the name becomes Potassium oxide.

16. The same applies here. Ca is Calcium and Cl is Chlorine but since its the non-metal at the end, it ends in -ide. So Calcium chloride.

17.The same applies here too. Al is Aluminium and S is Sulphur so Aluminium sulphide.

18. Calcium's symbol is Ca and that of Sulphur is S and that gives the formula CaS.

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What does graduated mean when talking about cylinders and beakers

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Has markings along the cylinder/beaker that indicate the volume of liquid inside them. .

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3 years ago

Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held

Cerrena [4.2K]

Answer : The heat energy absorbed will be, $1.23\times 10^5cal$

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(32.0^oC)$

The expression used will be:

$\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]$

where,

m = mass of ice = 1100 g

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$\Delta H_{fusion}$ = enthalpy change for fusion = $6.01kJ/mole=6010J/mole=\frac{6010J/mole}{18g/mole}J/g=333.89J/g$

Molar mass of water = 18 g/mole

Now put all the given values in the above expression, we get:

$\Delta H=1100g\times 333.89J/g+[1100g\times 4.18J/g^oC\times (32.0-0)^oC]$

$\Delta H=514415J=122948.1358cal=1.23\times 10^5cal$

Conversion used : (1 cal = 4.184 J)

Therefore, the heat energy absorbed will be, $1.23\times 10^5cal$

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3 years ago

Kathy is going to do an experiment in which she will grow bacteriain four prepared petri dishes:

mash [69]

Unwashed ==> Most bacteria

Sanitizer == Will have less than Unwashed

Washed ==> least amount of bacteria

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2 years ago

If 20.0g of CO2 and 4.4g of CO2

Ksivusya [100]

The given question is incorrect. The correct question is as follows.

If 20.0 g of $O_{2}$ and 4.4 g of $CO_{2}$ are placed in a 5.00 L container at $21^{o}C$ , what is the pressure of this mixture of gases?

Explanation:

As we know that number of moles equal to the mass of substance divided by its molar mass.

Mathematically, No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

Hence, we will calculate the moles of oxygen as follows.

No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

Moles of $O_{2}$ = $\frac{20.0 g}{32 g/mol}$

= 0.625 moles

Now, moles of $CO_{2} = \frac{4.4 g}{44 g/mol}$

= 0.1 moles

Therefore, total number of moles present are as follows.

Total moles = moles of $O_{2}$ + moles of $CO_{2}$

= 0.625 + 0.1

= 0.725 moles

And, total temperature will be:

T = (21 + 273) K = 294 K

According to ideal gas equation,

PV = nRT

Now, putting the given values into the above formula as follows.

P = $\frac{nRT}{V}$

= $\frac{0.725 mol \times 0.08206 Latm/mol K \times 294 K}{5.00 L}$

= $\frac{17.491089}{5}$ atm

= 3.498 atm

or, = 3.50 atm (approx)

Therefore, we can conclude that the pressure of this mixture of gases is 3.50 atm.

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3 years ago

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Flura [38]

Answer:

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3 years ago