4.9 moles of salt are required to be added to 1 kg water to change the boiling temperature
by 5°C.
<h3>What is the moles of Salt required to change the temperature of water by 5°C?</h3>
Based on the given equation, the molality of the solution is calculated as follows:
- Molality = change in temperature/ Kb × I
Change in temperature = 5 °C
Kb = 0.51
i = 2
Molality = 5/0.51 × 2 = 4.9 molal
Also, Molality = moles/kg of water
Moles of salt = molality × kg of water
Moles of salt = 4.9 × 1 = 4.9 moles.
Therefore, 4.9 moles of salt are required to be added to 1 kg water to change the boiling temperature
by 5°C.
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Answer:
Answers are in the explanation
Explanation:
Ksp of CdF₂ is:
CdF₂(s) ⇄ Cd²⁺(aq) + 2F⁻(aq)
Ksp = 6.44x10⁻³ = [Cd²⁺] [F⁻]²
When an excess of solid is present, the solution is saturated, the molarity of Cd²⁺ is X and F⁻ 2X:
6.44x10⁻³ = [X] [2X]²
6.44x10⁻³ = 4X³
X = 0.1172M
<h3>[F⁻] = 0.2344M</h3><h3 />
Ksp of LiF is:
LiF(s) ⇄ Li⁺(aq) + F⁻(aq)
Ksp = 1.84x10⁻³ = [Li⁺] [F⁻]
When an excess of solid is present, the solution is saturated, the molarity of Li⁺ and F⁻ is XX:
1.84x10⁻³ = [X] [X]
1.84x10⁻³ = X²
X = 0.0429
<h3>[F⁻] = 0.0429M</h3><h3 /><h3>The solution of CdF₂ has the higher fluoride ion concentration</h3>
Answer : The value of 
is -8.65 kJ/mol
Explanation :
The formula used for is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -16.7 kJ/mol
R = gas constant = 
T = temperature = 
Q = reaction quotient = 22.7
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -8.65 kJ/mol
