Is milk a solution, colloid, suspension, or a compound?

Write the full ground state electron configuration of f+.

ANTONII [103]

Answer:- $1s^22s^22p^4$ .

Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is $1s^22s^22p^5$ . $F^+$ is formed when F loses one electron from it's valence shell.

$F\rightarrow F^++1e^-$

Second shell is the valence shell for fluorine and so it loses one electron from 2p to form $F^+$ and the electron configuration of the ion becomes $1s^22s^22p^4$ .

7 0

3 years ago

According to valence bond theory, which orbitals overlap in the formation of the bond in hcl?

gulaghasi [49]

According to valence bond theory sigma bonds is formed when two orbitals approach and overlap over each other while pie bonds is formed when two orbitals overlap side by side. in formation of HCl 1s orbital of hydrogen overlap on 3p orbitals of chlorine

8 0

3 years ago

Read 2 more answers

The fluorocarbon compound c2cl3f3 has a normal boiling point of 47.6°c. the specific heats of c2cl3f3(l) and c2cl3f3(g) are 0.91

myrzilka [38]

<span>To raise the liquid temperature to the point of boiling take 1231.776 joules of energy. To convert to a gas takes 5320.645 joules. To raise to 108 degrees Celsius takes 1456.848 joules. Total amount of energy needed (as heat) equals 8009.269 joules or 8.009 kj.</span>

7 0

3 years ago

New questionWhat mass of calcium chloride (CaCl₂) would beproduced from the reaction of 125.9 g of hydrochloriacid (HCI) with ex

marshall27 [118]

Answer:

191.6 g of CaCl₂.

Explanation:

What is given?

Mass of HCl = 125.9 g.

Molar mass of CaCl₂ = 110.8 g/mol.

Molar mass of HCl = 36.4 g/mol.

Step-by-step solution:

First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O.$

Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:

$125.9\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=3.459\text{ moles HCl.}$

Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:

$3.459\text{ moles HCl}\cdot\frac{1\text{ mol CaCl}_2}{2\text{ moles HCl}}=1.729\text{ moles CaCl}_2.$

The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:

$1.729\text{ moles CaCl}_2\cdot\frac{110.8\text{ g CaCl}_2}{1\text{ mol CaCl}_2}=191.6\text{ g CaCl}_2.$

The answer would be that we're producing a mass of 191.6 g of CaCl₂.

4 0

1 year ago

I need help with these two questions

natulia [17]

I'm not sure about 2 but in 3 it would float

8 0

3 years ago