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777dan777 [17]
3 years ago
6

Is milk a solution, colloid, suspension, or a compound?

Chemistry
1 answer:
allsm [11]3 years ago
3 0
Milk is a colloid system
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Write the full ground state electron configuration of f+.
ANTONII [103]

Answer:- 1s^22s^22p^4 .

Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is 1s^22s^22p^5 . F^+ is formed when F loses one electron from it's valence shell.

F\rightarrow F^++1e^-

Second shell is the valence shell for fluorine and so it loses one electron from 2p to form  F^+  and the electron configuration of the ion becomes 1s^22s^22p^4 .


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3 years ago
According to valence bond theory, which orbitals overlap in the formation of the bond in hcl?
gulaghasi [49]
According  to  valence  bond  theory    sigma  bonds   is  formed when   two  orbitals  approach  and overlap  over  each  other   while     pie  bonds  is  formed  when   two  orbitals  overlap  side  by  side. in formation  of    HCl   1s  orbital  of  hydrogen  overlap  on   3p  orbitals  of  chlorine
8 0
3 years ago
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The fluorocarbon compound c2cl3f3 has a normal boiling point of 47.6°c. the specific heats of c2cl3f3(l) and c2cl3f3(g) are 0.91
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3 years ago
New questionWhat mass of calcium chloride (CaCl₂) would beproduced from the reaction of 125.9 g of hydrochloriacid (HCI) with ex
marshall27 [118]

Answer:

191.6 g of CaCl₂.

Explanation:

What is given?

Mass of HCl = 125.9 g.

Molar mass of CaCl₂ = 110.8 g/mol.

Molar mass of HCl = 36.4 g/mol.

Step-by-step solution:

First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O.

Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:

125.9\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=3.459\text{ moles HCl.}

Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:

3.459\text{ moles HCl}\cdot\frac{1\text{ mol CaCl}_2}{2\text{ moles HCl}}=1.729\text{ moles CaCl}_2.

The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:

1.729\text{ moles CaCl}_2\cdot\frac{110.8\text{ g CaCl}_2}{1\text{ mol CaCl}_2}=191.6\text{ g CaCl}_2.

The answer would be that we're producing a mass of 191.6 g of CaCl₂.

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I need help with these two questions
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I'm not sure about 2 but in 3 it would float
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