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alex41 [277]
4 years ago
11

What is the solution to the system of equations? {x=5y=2x−1 (5, 9) (9, 5) (5, 11) (11, 5)

Mathematics
2 answers:
Maksim231197 [3]4 years ago
8 0

Answer:

ooga

Step-by-step explanation:

booga

stepladder [879]4 years ago
6 0

Answer:

(5, 9)

Step-by-step explanation:

Given:

The equations to solve are:

x=5\\y=2x-1

Since the value of 'x' is given, we solve this system of equations using Substitution method.

We have to solve this by substituting in the value of 'x' from first equation into second equation.

Therefore, the second equation becomes

y=2(5)-1\\\\y=10-1\\\\y=9

Therefore, the values are: x=5, y=9

Hence, the solution is in ordered pair form is (5, 9).

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I gave the answer earlier, but here is the solution again, along with a graph proving it is correct.

8 0
3 years ago
Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.
faust18 [17]

Answer:

a. Tim has completed a greater amount of work.

b. Together they have completed \frac{142}{143} part of two projects.

Step-by-step explanation:

Let us assume that the project on which Jaime and Tim are working has x amount of space.

Now, given that Jaime has 5 over 11 space of a project completed while Tim has finished 7 over 13 space of the same project.

Therefore, Jaime has completed \frac{5x}{11} amount of space and Tim has finished \frac{7x}{13} amount of space.

a. Now, (7x) \times 11 > (5x) \times 13

⇒ \frac{7x}{13} > \frac{5x}{11}

Therefore, Tim has completed the greater amount of work. (Answer)

b. Together they have completed (\frac{7x}{13} + \frac{5x}{11}) = \frac{(7 \times 11 + 5 \times 13)}{13 \times 11} x = \frac{142}{143}x amount of space out of 2x amount of space. (Answer)

4 0
3 years ago
Lets be frineds :))))
tatiyna

Answer:

thanks :)

Step-by-step explanation:

7 0
3 years ago
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15. A decrease in value over time is known as:​
Liula [17]

Answer:

it's information presented unlawful

7 0
3 years ago
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Need help on this too ​
xeze [42]

Answer:

I think given or distributive property

Step-by-step explanation:

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