Answer:
1.44 g
Explanation:
The problem gives you the molarity and volume of the target solution, so right from the start you know that you can use that information to determine the number of moles of hydrochloric acid that it must contain.
So, molarity measures a solution's concentration in terms of how many moles of solute, which in your case is hydrochloric acid, you get per liter of solution.
A
0.158 M
hydrochloric acid solution contains
0.158
moles of hydrochloric acid for very liter of solution. Since you're dealing with
250 mL
, the equivalent of
1
4
th
of a liter, your solution will contain
250
mL
⋅
1
L
10
3
mL
⋅
0.158 moles HCl
1
L
=
0.0395 moles HCl
Now that you know how many moles of hydrochloric acid are needed to prepare your solution, use the compound's molar mass to convert this to grams
0.0395
moles HCl
⋅
36.46 g
1
mole HCl
=
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
1.44 g
a
a
∣
∣
−−−−−−−−−−
Explanation:
Please brainliest.
<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg
<em>Molar concentration
</em>
Assume you have 1 L solution.
Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)
= 1190 g solution
Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)
= 84.01 g NaHCO3
Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)
= 1.14 mol NaHCO3
<em>c</em> = 1.14 mol/1 L = 1.14 mol/L
<em>Molal concentration</em>
Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg
<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg
Nuetrons=neutral
protons =positive
electrons=negative
The answer is 4.0 moles of magnesium
because...
..
...4.0mol Makmol O2 =3.0mol O2
A B and C are all chemical changes. paper tearing is not.
