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dolphi86 [110]
3 years ago
12

A sample of aluminum, which has a specific heat capacity of , is put into a calorimeter (see sketch at right) that contains of w

ater. The temperature of the water starts off at . When the temperature of the water stops changing it's . The pressure remains constant at .Calculate the initial temperature of the aluminum sample. Be sure your answer is rounded to significant digits.
Chemistry
1 answer:
Oksanka [162]3 years ago
5 0

Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:

M=58g

Explanation:

From the question we are told that:

Heat Capacity H=0.897

Mass of water M=200g

Initial Temperature of Aluminium T_a=85.6

Initial Temperature of Water T_{w1}=16.0

Final Temperature of Water  T_{w2}=16.0

Generally

Heat loss=Heat Gain

Therefore

M*0.897*(85.6-20.1) =200*4.184*(20.1-16)

M=58g

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2 years ago
How many moles of hydrogen gas are needed to produce 20 grams of hydrochloric acid (HCl)?
Charra [1.4K]

Answer:

0.27 mole

Explanation:

Data given:

mass of hydrochloric acid (HCl) = 20 g

moles of hydrogen (H₂O) = ?

Solution:

First we look to the reaction in which hydrogen react with Chlorine and make hydrochloric acid (HCl)

Reaction:

              H₂ + Cl₂ -----------> 2HCl

Now look at the reaction for mole ratio

              H₂ + Cl₂ -----------> 2HCl

              1 mole                    2 mole

So it is 1:2 mole ratio of hydrogen to hydrochloric acid (HCl)

As we Know

molar mass of H₂ = 2(1) = 2 g/mol

molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Now convert moles to gram

                     H₂         +       Cl₂    ----------->     2HCl

            1 mole (2 g/mol)                             2 mole (36.5 g/mol)

                     2 g                                                 73 g

So,

we come to know that 2 g of hydrogen gives 73 g of hydrochloric acid (HCl) then how many grams of hydrogen will be required to produce 20 grams of hydrochloric acid (HCl).

Apply unity formula

                            2 g of H₂ ≅ 73 g of HCl

                            X g of H₂ ≅ 20 g of HCl

Do cross multiplication

                            X of H₂ = 2 g x 20 g / 73 g

                            X of H₂ = 0.55 g

Now convert grams of H₂ into moles

                    No. of moles = mass in grams/molar mass

Put values in above formula

                   No. of moles = 0.55 g / 2 (g/mol)

                   No. of moles = 0.27 mol

0.27 mole of hydrogen needed to produce 20 gram of hydrochloric acid (HCl).

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Add all the moles of gases.

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Divide O2 moles by total moles.

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