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2 years ago

Below is a word equation. Please follow directions for each part below.

Chemistry

1 answer:

alukav5142 [94]2 years ago

8 0

Answer:

CH3OH + 02 ----> C02 + H20

balanced equation -

CH3OH + 3/202 ----> C02 + 2H20

Use exactly the same process as the one used on another question of yours I answered.

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All of the following conditions of STP are true except A. 101.3 kPa B.3.81kPa.L/mol.K C. 24.2 L D. 273.15 K

Tasya [4]

The answer is c 24.2l

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2 years ago

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If we react 30 grams of ethane (C2H6 ) with 320 grams of oxygen, how many grams of carbon dioxide would we make

V125BC [204]

The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams

From the balanced equation of the reaction:

$2C_2H_6+7O_2---4CO_2+6H_2O$

The mole ratio of C2H6 to O2 is 2:7.

Mole of 30 grams C2H6 = mass/molar mass

= 30/30

= 1 mole

Mole of 320 grams O2 = 320/32

= 10 moles

Thus, C2H6 is the limiting reactant.

Mole ratio of C2H6 to CO2 according to the equation = 1:2

Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.

Mass of 2 moles CO2 = mole x molar mass

= 2 x 44

= 88 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

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2 years ago

3. What do you notice about the temperature of the substance in the test tube after it is placed in the beaker of water?

34kurt

Answer:

C: The temperature of the substance increases as it sits in the beaker of water

Explanation:

This question was taken from a video where an attempt was made to investigate the changes in temperature when a substance undergoes change from it's solid phase to its liquid phase.

To do this, as seen in the video online, it shows a solid substance in a test tube being placed in a beaker of water.

From observation, the water in the beaker has a warmer temperature than the solid substance present in the test tube and this in turn makes the test tube gradually increase in temperature.

Thus, the solid substance will as well increase increase in temperature when it is placed in the beaker of water.

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2 years ago

Which root word of the binary ionic compound ends with -ide?

kirill [66]

Sulfide would be an AWNSER but

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2 years ago

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Only a small fraction of a weak acid ionizes in aqueous solution. What is the percent ionization of a 0.100-M solution of acetic

Mademuasel [1]

Answer:

1.33%

Explanation:

In an aqueous solution, a weak acid such as acetic acid, will be in equilibrium with its conjugate base, acetate ion, thus:

CH₃CO₂H(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃CO₂⁻(aq )

Where dissociation constant, ka, is defined as the ratio of concentrations of products and reactants:

Ka = 1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]

<em>H₂O is not taken into account in the equilibrium because is a pure liquid</em>

<em />

When a solution of acetic acid becomes to equilibrium, the original concentration of the acid decreases producing more H₃O⁺ and CH₃CO₂⁻.

The concentrations at equilibrium when a 0.100M solution of acetic acid reaches this state, is:

[CH₃CO₂H] = 0.100M - X

[H₃O⁺] = X

[CH₃CO₂⁻] = X

<em>Where X is reaction coordinate.</em>

Replacing in Ka expression:

1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]

1.8x10⁻⁵ = [X] [X] / [0.100M - X]

1.8x10⁻⁶ - 1.8x10⁻⁵X = X²

1.8x10⁻⁶ - 1.8x10⁻⁵X - X² = 0

Solving for X:

X = -0.00135 → False solution. There is no negative concentrations.

X = 0.00133 → Right solution.

That means concentration of acetate ion is:

[CH₃CO₂⁻] = 0.00133M.

Now, percent ionization is defined as 100 times the ratio between weak acid that is ionizated, [CH₃CO₂⁻] = 0.00133M, per initial concentration of the acid, [CH₃CO₂H] = 0.100M. Replacing:

% Ionization = 0.00133M / 0.100M × 100 =

<em />

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2 years ago