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Jet001 [13]
2 years ago
15

Below is a word equation. Please follow directions for each part below.

Chemistry
1 answer:
alukav5142 [94]2 years ago
8 0

Answer:

CH3OH + 02 ----> C02 + H20

balanced equation -

CH3OH + 3/202 ----> C02 + 2H20

Use exactly the same process as the one used on another question of yours I answered.

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The electron configuration 1s2 is correct for an element that has 2 electrons, both in the first principle energy level
Molodets [167]

Answer:

The answer is True

Explanation:

I got it right on my quiz, hope this helps!

5 0
3 years ago
Is this correct? This is stoichiometry.
Viefleur [7K]
Yes it’s is bc I said so
7 0
3 years ago
Measurements show that the enthalpy of a mixture of gaseous reactants increases by 319kJ during a certain chemical reaction, whi
hram777 [196]

Answer:

the change in energy of the gas mixture during the reaction is 227Kj

Explanation:

THIS IS THE COMPLETE QUESTION BELOW

Measurements show that the enthalpy of a mixture of gaseous reactants increases by 319kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -92kJ of work is done on the mixture during the reaction. Calculate the change of energy of the gas mixture during the reaction in kJ.

From thermodynamics

ΔE= q + w

Where w= workdone on the system or by the system

q= heat added or remove

ΔE= change in the internal energy

q=+ 319kJ ( absorbed heat is + ve

w= -92kJ

If we substitute the given values,

ΔE= 319 + (-92)= 227 Kj

With the increase in enthalpy and there is absorbed heat, hence the reaction is an endothermic reaction.

8 0
3 years ago
If 18.7ml of 0.01500M aqueous HCl is required to titrâtes 15.00ml of an aqueous solution of NaOH to the equivalence point, what
sweet [91]

Answer:

0.0187 M

Explanation:

Step 1: Write the balanced neutralization reaction

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

18.7 mL of 0.01500 M HCl react.

0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.

Step 4: Calculate the molarity of NaOH

2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.

[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M

6 0
3 years ago
Which of the following would form a nonelectrolyte solution in water? A. KCl B. NaNO3 C. C6H12O6 D. Cu2SO4
ss7ja [257]
<span>C. C6H12O6

</span>This compound is covalent, and all salts are ionic compounds.
3 0
4 years ago
Read 2 more answers
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