Reactants: Potassium and Diboride Trioxide
Products: Potassium Oxide and Boron
Balanced equation: 6 K + 1 B2O3 -> 3 K2O + 2 B
Answer:
324.24 kPa
Explanation:
Given that;
Initial pressure P1 = 101325 Pa
V1= 400 ml
P2 = ?
V2= 125mL
From Boyle's law;
P1V1 = P2V2
P2 = P1V1/V2
P2= 101325 × 400/125
P2= 324.24 kPa
