Balance the following: CsH12 + 02 CO2+ | H20

What should you do if the high power objective lens touches or breaks the cover slip?

saul85 [17]

Tell your teacher. They'll know what to do and it's best to report it to them.

6 0

3 years ago

Instructions:

never [62]

Answer:

See explanation

Explanation:

A. Constitutional or structural isomers have the same molecular formula but different structural formulas.

B. Conformational isomers are compounds having the same atom to atom connectivity but differ by rotation about one or more single bonds.

C. Stereo isomers are compounds having the same molecular mass and atom to atom connectivity but different arrangement of atoms and groups in space.

I. Enantiomers are stereo isomers (optical isomers particularly) that are non-superimposable mirror images of each other.

II. Diasteromers are optical isomers that are not mirror images of each other.

Both diasteromers and enantiomers are types of optical isomers which in turn is one of the types of stereo isomers.

Stereo isomers differ from conformational isomers in that the arrangement of atoms in stereo isomers is permanent while conformational isomers results from free rotations in molecules about single bonds.

7 0

3 years ago

Which compound has the the highest melting point?

Kobotan [32]

The answer is
Al2(co3)3

5 0

3 years ago

Read 2 more answers

How much silver chloride is precipitated when 25.0 g of calcium chloride and 25.0 g of silver nitrate are mixed together in a be

Burka [1]

Answer:

21.09 g of AgCl

Explanation:

Hopefully the picture is clear and the method is understandable.

For more information go to

https://socratic.org/questions/5631d10b11ef6b4609a78ee2

7 0

3 years ago

At a certain temperature the value of the equilibrium constant, Kc, is 1.27 for the reaction. 2As (s) + 3H2 (g) ⇌ 2AsH3 (g) What

Bess [88]

Answer:

$0.887$

Explanation:

Hello,

In this case, the law of mass action for the first reaction turns out:

$Kc=\frac{[AsH_3]^2}{[As]^2[H_2] ^3}=1.27$

Now, for the second reaction is:

$Kc=\frac{[As][H_2] ^{3/2}}{[AsH_3]}$

Therefore, by applying square root for the first reaction, one obtains:

$\sqrt{Kc} =\sqrt{\frac{[AsH_3]^2}{[As]^2[H_2] ^3}} =\sqrt{1.27}$

$\frac{\sqrt{[AsH_3]^2} }{\sqrt{[As]^2} \sqrt{[H_2] ^3} } =\sqrt{1.27}$

$\sqrt{1.27}=\frac{[AsH_3]}{[As][H_2] ^{3/2}}$

Finally, since Kc is asked for the inverse reaction, one modifies the previous equation as:

$Kc'=\frac{1}{\sqrt{1.27} }=\frac{[As][H_2] ^{3/2}}{[AsH_3]}=0.887$

Best regards.

8 0

4 years ago