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sesenic [268]
3 years ago
12

A bakery sold blueberry and apple pies. The ratio of the number of blueberry pies sold to the total number of pies sold is 3 to

7. Which number c
Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Step One: State the givens for each type of pie

3 apple  

2 blueberry  

5 cherry  

6 lime  

Step Two: Calculate the total number of pies

3+2+5+6=16

Step Three: Find the percentage of blueberry

(blueberry)(100)=answer

(2/16)(100)=answer

12.5%=answer

∴12.5% of pies were blueberry

Sincerely, AmazingJasiah

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Answer:

A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.

Step-by-step explanation:

State the null and alternative hypotheses to be tested  

On this case we can assume that the researcher conduct a one right tailed test hypothesis like on this way:  

Null hypothesis:\mu \leq \mu_o  

Alternative hypothesis:\mu > \mu_o

The statistic for this case is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

On this case we have the value for z score given z =+1.85

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05,0.01. The next step would be calculate the p value for this test.  

Since is a one right tail test the p value would be:  

p_v =P(z>1.85)=1-P(Z  

If we compare the p value obtained and the significance level given \alpha=0.05,0.01 we can take a decision:

A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.

YES, since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level. And for the significance level 0.05 we have that p_v and we can reject the null hypothesis.

B) The researcher should reject the null hypothesis with either a = .05 or a = .01.

No since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level

C) The researcher should fail to reject H0 with either a = .05 or a = .01.

No, for the significance level of 0.05 we reject the null hypothesis since p_v

D) This cannot be answered without additional information.

No, we have enough info to answer the question

4 0
3 years ago
SOMEONE PLEASE HELP ME WITH MY HOMEWORK ILL DO ANYTHING FOR HELP BUT JUST PLEASE HELP ME
PilotLPTM [1.2K]

Answer:

6

Step-by-step explanation

divide 48/6=6

divide 90/15=6

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7 0
2 years ago
3=x+9<br> PLEASE SHOW WORK. SOLVE AND CHECK.
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Answer:

x = —6

Step-by-step explanation:

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What is the value of x?<br> Enter your answer in the box
klasskru [66]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
The number of airline passengers in 1990 was 466 million. The number of passengers traveling by airplane each year has increased
taurus [48]

Answer:

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Step-by-step explanation:

We have been given an exponential growth formula P(t)=466\cdot 1.035^t, which represents number of passengers traveling by airplane since 1990.

To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:

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Take natural log of both sides:

\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)

Using property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)

0.658209129198=t\cdot 0.034401426717

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This means that in the 20th year since 1990, 900 million passengers would travel by airline.

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Therefore, 900 million passengers would travel by airline in 2010.

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