The right answer is B.
The first step to answering this question is combining all like terms.
A. 2x + 2 + 2x + 3x - 8
The like terms in this expression are the x terms and the constants
So, what you would do is combine all of the x terms and combine all of the constants
(2x + 2x +3x) + (2 - 8)
7x - 6
B. 4 + 7x - 2
In this expression, you would combine all of the constants
7x + (4 - 2)
7x + 2
C. -2 + 5x + 2x - 4
For this expression, you would again, combine all of the x terms and all of the constants.
-2 + 5x + 2x - 4
(5x + 2x) + (-2 - 4)
7x - 6
D. 8x - x - 6
For this expression, you would combine all of the x terms
8x - x - 6
(8x - x) - 6
7x - 6
Now let's look at all of the new answer choices:
A. 7x - 6
B. 7x + 2
C. 7x - 6
D. 7x - 6
The question is asking you to find the one expression that's different. The only different one is B, so that's the answer.
Answer:
-15 would be the answer because if it's below sea level it would have a negative sign in front of 15
Step-by-step explanation:
Answer:
The midpoint of the x-intercepts of the function is (0, 0)
Step-by-step explanation:
Notice that since the function comes in factor form, we know that its roots (which are actually the intercepts the function has with the x-axis) are: x = 4 and x = -4 (the x-values for which the function renders zero).
These two points are equidistant from the origin of coordinates (0, 0), and therefore the midpoint of these x-intercepts is (0, 0).
Answer:
Step-by-step explanation:
The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.
Thus, since John already knows that 
and 
, therefore, an additional information showing that the angle between 
and 
in ∆ABC is congruent to the angle between 
and 
in ∆DEF.
For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be .
See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.
